- IBPS BANK CLERK CWE ( Mains Exam) 2017

# IBPS BANK CLERK CWE ( Mains Exam) 2017

### GENERAL AWARENESS

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(3)Identi er

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(1)NEFT

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(4)IPPB

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(5)Netherland

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(1)Payment

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(2)Manipur

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(4) 74%

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(3)Mumbai

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(4)USA

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(2)Repo Rate

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(4)NPCI

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(5)Kehkashan Basu

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(3)Achieving 17 Goals for the future we want

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(5)Private Shareholders.

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(1)Netherlands

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(4)districts

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(2)Chennai

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(5)Specikc risk

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(2)Amish Tripathi

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(5)Kerala

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(3)Amritsar

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(2)dormant account

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(2)Manoj Bajpayee

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(5)NACH

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(4)84 months

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(1) Rs.2,000/-

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(2)Carnatic singer

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(4)Promissory note

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(3)China

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(3)Dubai

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(4)Twelve

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(1)Micro Credit

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(2)Snapdeal

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(4)Bandhan Financial Services Private Limited

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(2) 25%

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(4)Sudarshan Sen

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(5)National Se.curitiesDepository Limited (NSDL)

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(4)IDRBT

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### COMPUTER KNOWLEDGE

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(1)Encryption

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(2)Voice Over Internet Protocol

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(1)Number of keys in the keyboard.

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(5)Find

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(3)permanent data

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(4)Worms

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(1)Batch processing

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(2)emails infects computer.

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(4)website.name@website.com

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(5)Unicode

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(2)Rich Text Format

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(2)Left justify

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(1)It is the property of the toolbar.

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(1)Platform independent

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(1)Phishing

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(1)Database

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(1)Processing

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(4)Control unit

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(1)RDBMS

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(1)FORTRAN

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(4)Simplex

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(5)Presentation layer

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(1)The operating system

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(3)Very resistant to interference

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(2)delete directory

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(2)Program

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(3)Formatting

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(1)Compression

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(1)data mining

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(3)Computer forensics

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(4)Information

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(3)System unit

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(1)Motherboard

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(1)Nanotechnology

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(1)instructions

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(1)System unit

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### ENGLISH LANGUAGE

Directions (1-5): In each of the following questions, each sentence has some blank spaces. Fill in the blanks with appropriate words out of the given alternatives.

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(5)patriarchal, prohibits, guardian

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(2)decreasing, increased

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(5)impose, volatility

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(1)expected, essential

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(2)likely, weaker

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Directions (6-13): Read the the following passage and answer the given questions. Certain words/phrases have been given in bold to help you locate them while answering some of the questions.

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(3)Only A

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paste_right_option

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(1)Only C

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(5)All A, B and G

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(3)A and B

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(2)A and B

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(2)It caused stagnation of trade in the 1990s.

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(5)All A, B and C

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Directions (54-58): In these questions, a sentence is given with three words/group of word\$, in bold type. One or more of them may have a certain error. Below the sentence are given three combinations of words/group of words i.e. (A), (B). and (C). You have to find out the correct word/group of words from among (A), (B) and (C) given below each sentence to replace the incorrect words and make the sentence grammatically correct and meaningful. One, two, all three or none of them may be correct. Decide upon which is/are correct, if any and mark the correct option which denotes your answer. If the sentence is correct as it is, mark `No correction required’ as your answer.

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(4)Only C

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(5)No correction required

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(4)Only A

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(4)Only C

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(1)Only A

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Directions (19-23) : In these questions, there are four/five sentences (A), (B), (C), (D) and/or (E). Three or four of these sentences contribute to one main idea when these sentences are formed into a paragraph. One sentence does not contribute to that main idea. That sentence is your answer.

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(2)Only B

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(2)Only C

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(1)Only A

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(5)All those given as options contribute

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(3)Only C

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Directions (24-30): Read the following passage carefully and answer the questions given. Certain words/phrases are given in bold to help you locate them while answering some of the questions.
Intended to give its workers more rest, this year, the Taiwanese government has brought about some labour amendments such as the “one kxed day off, one flexible day off’. It has steadily garnered raked reactions in the media. News of businesses moving to enact measures to meet the new regulations has emerged, including price hikes and reduced business hours. Reports such as popular food chains upping their prices have coloured media. On the other hand, Taiwan’s two major convenience stores denied reports that stores would be closing over the weekend in response to the regulations. The latest circumstances only presented examples of how the new holiday policy would hinderTaiwanese businesses’operations, pose price hikes and create a more difkcult environment for Taiwanese nationals to go about their daily lives in an already wage-stagnant economy.
Increased costs are inevitable. But should it be looked upon with disdain and diversion? Let us look at the issue from a different perspective. Foreigners and tourists have commented that the 24-hour convenience stores and high quality of service have left a positive impression about the country. That should be a point of pride for Taiwan, but on the other hand, the new holiday policy also provides an opportunity to spur change as Taiwan’s laudable conveniences also come along with their own set of burdens.
It’s still too early to say whether President and his party’s holiday policy would improve working conditions. Taiwan’s businesses should look out for its employees’ well-being instead of their costs, while the government must similarly look out for businesses and the people at large to ensure effective policy progress. There is no doubt that the Taiwan’s working environment is in need of change, and the new holiday policy provides a platform for that. However, whether it would bring about a good or bad change ultimately is left up to how the key players-businesses, the government and the people-respond.

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(3)Complain

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(2)Only D

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(5)None of A, B and C

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(1)It should be implemented judiciously and must not be taken unique advantage of.

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(4)Employment opportunities in Taiwan will cease.

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(5)All A, B and Care not true

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(4)A and C

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(2)All A, B and C

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(2)All A, B and C

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(5)None

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(1)A and C

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Directions (36-40): Read each of the following four sentences to find out whether there is any grammatical error in it. Choose the sentence with no grammatical error as the correct answer. If all the given sentences are grammatically correct, mark No error’ as your answer.

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D

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(1)A

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(4)D

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(4)D

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(2)A

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### QUANTITATIVE APTITUDE

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(4)40

1. Explanation :

Let the speed of the bus when it halts = x km/h Speed of the bus when it travelled = (x +4) km/h
According to question, $$\frac{60}{x}-\frac{60}{x+4} = \frac{10}{60}*60*[\frac{x+4-x}{x*(x+4)}] = \frac{1}{6}*1440=x^2+4x$$
x² + 4x —1440 =0
x² + 40x — 36x —1440 = 0 x (x + 40) – 36 ( x + 40) = 0
(x­36) (x+ 40) = 0
x=36, – 40
∴ Speed of the bus when it travelled = 36 + 4 = 40 km/h

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(5) Rs.1,15,200/-

1. Explanation :

Let the monthly income of Duggabati = Rs. x
According to question, $$x*(100-24-30)*\frac{1}{100}*\frac{9}{16}*12 = 124200$$
$$x*\frac{46*9}{100*16} = 10350$$
$$x = \frac{1150*1600}{56}$$
x = Rs.40,000/­
∴ Duggabati spent on paying rent in a year
$$=40000*\frac{24}{100}*12$$= Rs.1,15,200 /­

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(4) 34.4

1. Explanation :

Let the speed of boat in still water = 9a Speed of current = a
According to question,
(9a + a) — (9a — a) = 3
10a – 8a = 3
2a =3
$$a = \frac{3}{2}$$
$$\frac{x}{9a+a}+\frac{x-5}{9a-a}$$
$$\frac{4x-5x-25}{60}=\frac{285}{60}$$
⇒ x = 34.4 km

The data given below are regarding percentage of fction books sold by fve bookstores in the months of June and December in the year 2002. All the bookstores sold either fction or non-fction books

Note : Total number of books sold = Fiction + Non-kction

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(3) 1200

1. Explanation :

Let the number of fiction books sold by store B inJune = x
Number of non fiction books sold by store B inJune =$$x*\frac{20}{80}$$
Number of fiction books sold by store B inDecember = x + 200
Number of non fiction books sold by store B inDecember = $$(x+200)*\frac{30}{70}$$
According to question,
$$x+\frac{20x}{80}+x+200+(x+200)*\frac{30}{70}=2000$$
$$\frac{75X}{4*7}=-\frac{2000*6}{7}$$
x = 640
Total number of books sold by store B in December =$$200+x+(x+200)*\frac{3}{7}$$
=1200

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(5) 1900

1. Explanation :

Total number of non­fiction books sold by store C =$$1500*\frac{60}{100}+2000*\frac{50}{100}$$
= 900 + 1000 = 1900

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(4) 12.5%

1. Explanation :

Let the number of fiction books sold by store D in June = x
Number of non fiction books sold by store D in June = $$x*\frac{28}{72}$$
Total number of books=$$\frac{25x}{18}$$ Number ­of fiction books sold by store D in June = x
Number of non fiction books sold by store D inDecember = $$x*\frac{36}{64}$$
Total number of books=$$\frac{25x}{16}$$
∴ Required percentage = 12.5%

Ans .

(5) 1548

1. Explanation :

Total number of books sold by store E in June =1800
Total number of books sold by store E inDecember = $$1800*\frac{100}{75}$$=2400
Total number of fiction books sold by store E =$$1800*\frac{30}{100}+2400*\frac{42}{100}$$ =540 + 1008 = 1548

Ans .

(3) 660

1. Explanation :

Let the number of fiction books sold by store A in June = x
Number of non fiction books sold by store A in40June= $$x*\frac{40}{60}$$
Number of fiction books sold by store A in December = x
Number of non fiction books sold by store A in December = $$x*\frac{45}{55}$$
acording to question, 5x = 60 × 33 ⇒ x = 12 × 33 = 396 Total number of books sold by store A in June=$$396+396*frac{2}{3}$$= 396 + 264 = 660

Directions (9-13) : Refer to the pie charts and answer the given questions.

The following data are regarding number of students(Boys + Girls) studying in standard Xth of various schools(A, B, C, D and E) in the year 2010Total number of students(Boys + Girls) = 3000

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(5) 660

1. Explanation :

Total number of students in schools A and B together
$$=3000*\frac{(10+23)}{100}$$
= 30 × 33 = 990
Total number of students in schools D and E together
$$=3000*\frac{25+30}{100}$$ =30 x 55 = 1650
∴ Required difference = 1650 – 990 = 660

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(4)$$55*\frac{5}{9}$$

1. Explanation :

Number of boys studying in school C $$=1600*\frac{10}{100}=100$$
Number of students studying in school C $$=3000*\frac{12}{100}=360$$
Number of girls studying in school C = 360 – 160 = 200
Required percentage = $$55*\frac{5}{9}$$

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(2) 288

1. Explanation :

Average number of boys studying in schools A and B
$$=(\frac{1600*11}{100}+1600*\frac{25}{100})*\frac{1}{2}=288$$

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(5) 34%

1. Explanation :

Number of boys studying in school E $$=1600*\frac{24}{100}=384$$
Number of students studying in school E $$=3000*\frac{30}{100}=900$$
Number of girls studying in school E = 900 – 384 = 516
∴ Required percentage = $$=\frac{516-384}{384}*100$$ = 34.375 = 34%

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(2) 16 : 9

1. Explanation :

Number of boys studying in school D $$=1600*\frac{30}{100}=480$$
Number of students studying in school D $$=3000*\frac{25}{100}=750$$
Number of girls studying in school D = 750 – 480 = 270
∴ Required ratio = 480 : 270 = 16 : 9

Directions (14-18): Study the following information carefully and answer the given questions.

The following data are regarding total number of male and female employees (MBAs and non-MBAs) working in three organizations—A, B and CIn organisation :

In organisation :

A: 30% of the total number of employees are females, of which 10% are MBA’s. In organization, 168 males are MBAs which are 20% of total number of males.
B: 40% of the total number of employees are females, of which 25% are MBAs. 10% of the total male employees in organization B are MBAs. The total number of female employees in organization B are equal to that in organization A.
C: Total number of female employees are twice of that in organization B. 20% of the total number of male employees and 20% of the total number of female employees are MBAs. Number of male employees who are not MBAs are 672 more than that of female employees who are not MBAs.

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(4) 26

1. Explanation :

Total number of male MBA employees in both the organizations = 54+ 312 = 366
Total number of male employees who are science graduates = 366 ­262 = 104
∴ Number df male MBA employees who are science graduates in organization B$$=104*\frac{1}{4}=26$$

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(4) 240

1. Explanation :

Required difference = (672 + 324) – (486 + 270) = 996 ­756 = 240

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(5) 480

1. Explanation :

Required percentage $$=\frac{360+360+720}{36}$$ = 480

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(1) 68%

1. Explanation :

$$=\frac{1560}{1560+720}*100$$ = 68.42 ≈ 68%

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(5) 90%

1. Explanation :

Total employees in organization A = 840 + 360 =1200 Total employees in organization C = 1560 + 720 = 2280
∴ Required percentage$$=\frac{2280-1200}{1200}*1200=$$ 90%

Directions (19-23) : Study the table and answer the given questions.
Data related to rating of 5movies in two cities (X and Y)

Note: I. Few data are missing (indicated by—). You need to calculate the value based on given data, if required, to answer a given question.
II. Total sum of ratings obtained = Number of raters x Average rating obtained

Ans .

(1) 73.5

1. Explanation :

Total sum of rating obtained from city X / Total sum of ratings obtained from city Y$$=\frac{16}{21}$$
$$\frac{84*72}{108*a}=\frac{16}{21}$$
a = 73.5

Ans .

(4) 20%

1. Explanation :

For movie D,
Let the number of raters in city X = x
Number of raters in city Y = y ∴$$x=65=y*84 i.e. \frac{x}{y}=\frac{3}{2}$$
x : y = 3 : 2 = 6 : 4
y : z = 4 : 5
x : y : z = 6 : 4 : 5
∴ Required percentage = 20%

Ans .

(1) 35%

1. Explanation :

For movie B,
Let the average rating obtained from city X = x
Average rating obtained from city Y = $$\frac{9X}{10}$$ Total sum of ratings obtained from city X=120x
Total sum of ratings obtained from city Y=180 x­9x =162x10162x­120x.*.
Required perLentage – x100120x42 x100=35% 120

Ans .

(2) 36

1. Explanation :

In city X,
Let male raters = 50 Female raters = 30
Average rating of males = x
Average rating of females =y
$$\frac{50x+30y}{80}=42.75$$ 5x + 3y = 342
In city Y,
Male raters = 20 Female raters = 10 $$\frac{29x+10y}{80}=42$$
2x + y=126
⇒ 6x + 3y = 378 Subtracting equation (i) from equation (ii),
x = 36

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(4)$$58*\frac{1}{3}%$$

1. Explanation :

For movie A, Raters from city X = x
Raters from city Y = y
According to question, $$=\frac{x+46+y*77}{x+y}=58$$
46x + 77y = 58x + 58y
$$\frac{x}{y}=\frac{19}{12}$$ Required percentage =$$58*\frac{1}{3}%$$

Ans .

(5) Other than those options

1. Explanation :

1According to question, 18W + 24 = 24M × 15 18W =15M
6W = 5M
16 women work for 3 days.
∴ Remaining work = 7 / 9 20M + 16W = 4 × 5M + 16W = 4×6W + 16W = 24W + 16W = 40W
In women complet a work in 24 days.
By formula, ans:$$8*\frac{2}{5}$$days

Ans .

(3) Rs.500/-

1. Explanation :

Let the cost price of article A = Rs. x
cost price of article B = 6x / 5
Maked price of article A = 3x / 2
Maked price of article B = 3x / 2 According to question,
⇒ x = RS.500/­

Ans .

(3) 46

1. Explanation :

Let Ram’s present age = x years
According to question, x + 17 = 2x – 6
x = 23 yearp
Vivian’s present age = 21a
Amit’s present age =19a According to question, 19a+31 = 3 x 23
19a = 69 – 31
19a = 38
a = 2 years
∴ Vivian’s age 4 years hence = 21 x 2 + 4 =42 + 4 = 46 years

Ans .

(5) 12

1. Explanation :

Quantity of apple juice in mixture was taken out from Jar A = 25 litre
Quantity of water in mixture was taken out from Jar A = 5 litre
In Jar B, Quantity of mango juice = 20 litre
Quantity of water Total mixture in Jar C = 30 + 30 =60 litre
Ratio of apple juice) mango juice and water in Jar C
= 25 : 20 : (5+10) = 25 : 20 : 15 = 5 : 4 : 3
Mixture taken out from Jar C =12 litre
Remaining mixture in Jar C = 60 – 12 = 48 litre
∴ Resultant quantity of water in Jar C = 12 litre

Directions (28-32) : What approximate value will come in place of question mark (?) in the given questions ? (You are not expected to calculate the exact value)

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(3) 13

1. Explanation :

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(3) 39

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(5) 330

1. Explanation :

1056 × ? ÷ 3 = 576.73 × 202
352 × ? ≈ 577 × 202
∴ ? ≈ 330

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(4) 790

1. Explanation :

64 × 13 – 42 ≈ ?
832 – 42 ≈ ?
∴ 790 ≈ ?

Ans .

paste_right_option

1. Explanation :

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Directions (33-37) : These questions consist of a question and two/three statements numbered I, II and III are given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read the statements and choose the appropriate option.

Ans .

(1)Either statement I or statement II and statement III are sufkcient to answer the question.

1. Explanation :

From statement I,
Let the number of cards in a bag = 2n or 2n + 1
When the number of cards = 2n
∴ Even numbered card = n ∴ Required probability = 7/31
31n – 31 = 28n ­14
31n – 28n = 31­ 14
3n = 17 ⇒ n = 17/3
When number of cards = 2n + 1
∴ Ecen numbered card = n
∴ Required probability = 7/31
31 n – 31 = 28 n + 14
31n – 28n = 31 + 14
3n = 45 ⇒ n = 15
∴ Total number of cards = 2n + 1 = 2 × 15 + 1 = 31 From statements II and III,
Number of card = 16 + 15 = 31

Ans .

(5)Any two of the three statements are sufkcient to answer the question.

1. Explanation :

From statements I and III
$$9331.20 = 8000[1+\frac{R}{100}]^2$$
R = 8%
From statements I and II,
$$9331.20 = P[1 + \frac{R}{100}]^2$$ ......(i)
Diff = $$\frac{PR^2}{10000}$$
i.e. $$51.20 = \frac{P^2R^2}{10000}$$ .......(ii)
Dividing equation (i) by equation (ii),
R = 8%
From statements II and III,
R = 8%

Ans .

(4)Any one of the statements is sufkcient to answer the question.

1. Explanation :

From statement I,
P’s 1 day’s work.= 1/8
Q’s 1 day’s work = 1/5
∴ Q can complete the work =5 days From statement II,
(P + Q)’s 1 day’s work
Qs, 1 day’s work = 1/5
Q can complete the work =5 days Worn statement. III,
Q’s 1 day’s work = 1/5
∴ Q can complete the work = 5 days

Ans .

(5)Any two of the three statements is sufkcient to answer the question.

1. Explanation :

From statement I and II,
a + b = 14 …….(i)
a² + b² = 106 …..(ii) (a+b)² = a² + b² + 2ab (14)² = 106 + 2ab
2ab = 196 – 106 = 90
ab = 45
∴ (a­b)² = (a+b)² – 4ab
(a­b)² = (14)² – 4 × 45
= 196 – 180
(a­b)² = 16
a­b = 4 ….(iii)
Adding equation (i) and equation (iii), 2a = 18 ⇒ a = 9
b = 14 ­9 = 5
a³ + b³ = (9)³ + (5)³ = 729 + 125 = 854
From statements II and III, a² + b² =106 a =b – 4
(b – 4)² + b² =106 b²+ 16 – 8b + b² =106 2b² ­8b ­90 =0 b² ­4b ­45 =0
b² ­9b + 5b – 45 =0 b (b ­9)+5 (b ­9) =0 (b­9)(b+5)=0
b =9
a =9 – 4 = 5 =0
a³ +b³ =(9)³ + (5)³ = 729 + 125 = 854
From statements III and I, a + b =14 a = b – 4
b – 4+ b =14
2b =18
b =9 ⇒ a = 9 – 4 = 5
a³ + b³ = (9)³ + (5)³ = 729 + 125 =854

Ans .

(5)All three statements are sufkcient to answer the question.

1. Explanation :

From statement I, Let HCF = x
LCM =24x
From statement II, 24x + x = 400 2 5x = 400
x =16
HCF =16
LCM =16 × 24=384
From statements I, II and III,
First number × Second number = HCF × LCM
∴ Second number = 48

Ans .

(4) 112

1. Explanation :

--- Let the side of square = 2a Then, radius of circle = C1 = a
Diagonal of square
Then, radius of circle C2 = a*2^1/2
According to question, a=14cm
∴ Perimeter of the square = 4 × 2 × 14 = 112 cm

Ans .

(4) Rs. 16,350/-

1. Explanation :

--- First condition,
Principal = Rs. P, Time = T years
S.I. = Rs.P
Rate = 100/T
Second condition, Time = 2T years
∴S.I. = Rs.10,900
∴ Amount = 10900 + 5450 = Rs.16,350/­

Ans .

(1) Rs.4,800/-

1. Explanation :

Let the initial investments of A, B and C be 2x, 3x and 4x respectively.
After 6 months, the investments of A, B and C be 3y, 2y and y respectively.
Ratio of investments
= (2x × 6 + 3y × 6) : (3x × 6 + 2y × 6) : (4x × 6 + y × 6) = (2x + 3y) : (3× + 2y) : (4x + y)
Rational addition =2x + 3y + 3x + 2y + 4x + y = 9x + 6y
If total annual profit = z
B’s share in profit = $$\frac{3x+2y}{9x+6y}*z$$
C’s share in profit = $$\frac{4x+y}{9x+6y}*z$$
i.e. 5x = 10y
x = 2y .....(i)
B’s share in profit­A’s share in profit = 200
$$(\frac{3x+2y}{9x+6y} - \frac{2x+3y}{9x+6y})z = 200$$
i.e. z = Rs.4,800/- + 8y ⇒ 5x = 10y x = 2y

### REASONING

Directions (1-4): Study the following information carefully to answer the given questions.

In a certain code language,"work for earning money" is coded as “Go3 None5 Xor4 Farnin7", “like six years passed" is coded as “Ti3 Qasse6 Zear5 Mik4" “hence good amount received" is coded as “Seceive8 Lenc5 Hoo4 Bmoun6"

Ans .

(3)None5 Mas4 Farnin7 Xa3

1. Explanation :

As, work = Xor4
Similarly, for → Eo3
earning → Farnin7
money → None5
(i)like → Mik4 Six → Ti3 years → Zear5 passed → Qasse6
(ii)hence → Ienc5 good → Hoo4 amount → Bmoun6 received → Seceive8
Solution: 3
last → Mas4 earning → Farnin7 was → Xa3 money → None5

Ans .

2)Hoo4 Qerfec7 Blway6 Qeop16

1. Explanation :

good → Hoo4 people → Qeopl6 always → Blway6
perfect → Qerfec7

Ans .

(1)Blway6 Lance5 Xron5 Lenc5

1. Explanation :

--- hence → Ienc5
always → Blway6
wrong → Xron5
hance → Ianc5

Ans .

(5)Garmin7

1. Explanation :

farming → Garmin7

Directions (5-10): Read the given information carefully and answer the given questions.

There are kve units i.e. 1, 2, 3, 4 and 5. Each unit has a different height. Also each unit contains books and boxes. Unit 2 is above Unit 1 and Unit 3 is above Unit 2 and so on. Every unit belongs to different country i.e. Beijing, Paris, London, Sydney and Zurich. The total height of all kve units is equal to 252 ft.
•Total height of unit is equal to the total height of books plus total height of boxes in each unit.
•Height of books is not equal to the height of boxes, unless speciked.
The books belongs to London is an even unit. The total height of Unit 1 is 75 ft. Sydney is not a Unit 1. The total height of unit, which belongs to Sydney, is 55 ft. There is only one gap between London and Paris. The height of books and height of boxes in Unit 3 are equal. The height of books in Unit 2 is not less than 30 ft. The books in Unit 4 are four more than books, which is in Unit 3. The total height of London is not 37 ft. The total height of unit, which contains 37 ft is not taking the place which is immediately above a unit, which contains ’20 ft more than the unit, which belongs to Sydney. The height of boxes in Unit 2 is 23 ft. Unit belongs to Zurich does not contain the equal height of books and boxes. The total height ofUnit 2 is an odd number and height is more than 50 ft and less than 55 ft. Unit 1 contains 23 ft height of boxes more than Unit 4 contains height of boxes and Unit 5 contains 7 ft height of books less than Unit 1 contains.

Ans .

(2)32 ft

1. Explanation :

---

Ans .

(4)Beijing

1. Explanation :

---

Ans .

(4)32 ft

1. Explanation :

---

Ans .

(2)32 ft

1. Explanation :

---

Ans .

(2)17 ft

1. Explanation :

---

Ans .

(1)Unit 2

1. Explanation :

---

Directions (11-15): Read the given information carefully and answer the given questions.

Two buses-A and B start their journey from same depot but not necessary in the same order. Bus A starts moving 6 km towards north direction to -Point P and then takes a right turn and moves 18 km to reach Point R, then take a left turn and ? roves 12 km to reach Point S. Points P, Q and R lies in a same line. Distance between P and Q is half of the distance between Q and R. Bus B starts to move towards west 2 km more than Point Q and R from Depot and reach Point W, then take a right turn and walk 18 km to reach Point U. U, V and W lies in the same line as distance of V and W is double of the distance between U and V. From Point U Bus B take a right turn and reach Point S. Point T lies between U and S in exact midway.

1.

Ans .

(2)32 km

1. Explanation :

Total distance between U and S = 14 + 18 = 32 km

Ans .

(4)North-east

1. Explanation :

---

Ans .

(2)From Point V he should go to east direction 14km than move toward south and reach depot

1. Explanation :

---

Ans .

(3)16 km

1. Explanation :

Distance between T ans S = $$\frac{14+18}{2} = 16km$$

Ans .

(4)North

1. Explanation :

---

Directions (16-20) : In each of these questions, two statements marked as I and II are provided. These may have a cause and effect relationship or may have independent causes or be the effects of independent causes.

Ans .

(2)

1. Explanation :

---

Ans .

(4)

1. Explanation :

---

Ans .

(5)

1. Explanation :

---

Ans .

(1)

1. Explanation :

---

Ans .

(2)

1. Explanation :

---

Directions (21-25) : Study the following information and answer the questions below.

J, K, L, M, N, 0, P and R are sitting around a circular table facing the centre. Each of them was born in a different year-1971, 1975, 1979, 1980, 1981, 1984, 1985 and 1990, but not necessarily in the same order.
M is sitting second to the right of K. L is sitting third to the right of J. Only the one born in 1984 is sitting exactly between J and K N, who is the eldest is not an immediate neighbour of J and M. R is older than only M. R is sitting second to the left of P. P is not an immediate neighbour of N. J is younger than L and 0. K was born before 0 but he is not second eldest.

Ans .

(2)L

1. Explanation :

---

Ans .

(5)The one born in 1981

1. Explanation :

---

Ans .

(4) 1985

1. Explanation :

---

Ans .

(1)K is sitting third to the right of R

1. Explanation :

---

Ans .

(3)The one born in 1981

1. Explanation :

---

Directions (26-30) : Study the following information carefully and answer the given questions.

Eight persons—I, J, K, L, M, N, 0 and P are sitting around a circular table but not necessarily in the same order. Three of them are facing outward while kve are facing towards the centre.M is third to the right of K. N is sitting third to the left of M. Three persons are sitting between N and J. 0 is sitting third to the right of N, who is not facing the centre. L is sitting third to the right of I, who is not facing the centre.

1.

Ans .

(5)P

1. Explanation :

---

Ans .

(5)All the given statements are true

1. Explanation :

---

Ans .

(1)IKN

1. Explanation :

---

Ans .

(3)K is third to the left of P.

1. Explanation :

---

Directions (31-33) : These questions consist of a question and three statements numbered I, II and III given below it. You have to decide whether the data provided in the statements are sufficient to answer the question.

Ans .

(3)

1. Explanation :

1.

Ans .

(2)If all the statements I, II and III taken together are not sufkcient to answer the question.

1. Explanation :

Ans .

paste_right_option

1. Explanation :

From all statements,
P S T Q R

Ans .

(5)If the statements I and III are sufkcient to answer the question but statement II alone is not sufkcient to answer the question.

1. Explanation :

---

Ans .

(5)The introductory scheme of free gift voucher with the tea was withdrawn from the market within 15 days of launch of the product.

1. Explanation :

---

Directions (36-40) : Read the given information carefully and answer the given questions.

There are seven persons in a family namely A, B, C, D, E, F and G. All of them related with each other in an order. All of them have a different age.A is older than B but younger than E. The third oldest person in the family is 38 years old. B is the sister of A. C is the father of A. The third youngest person of the family is 35 years old. G is the oldest person of .the family. B is the niece of F. E is older than B. F is the husband of E. G and D are married couple. C’s mother is 69 years old. C is younger than F. Oldest person of the family is male member.

1.

Ans .

(4)F

1. Explanation :

---

Ans .

(3)6 years

1. Explanation :

B’s age = 75 – 69 = 6 years

Ans .

(3)Grandmother

1. Explanation :

---

Ans .

(2)E

1. Explanation :

---

Ans .

(3)37 years

1. Explanation :

---