**Explanation :**If you are retaining right, your opponent can either retain upper or retain lower. Your next

move would depend on what your opponent has done as he plays to minimize your gain and

you play to maximize your own gain.

Since, your next move is retain to right again, it is evident that your opponent would have

chosen 'retain lower' in his first move.

You can think of this as follows:

If your opponent's first move is to retain upper, the grid you would get is:

In this case, your next move would logically be to 'retain left' as you would then expect a

minimum of 4. In case from the above situation you go to retain right, you would then only

expect to get a return of '1' from the game.

Since, it is given that you chose to retain right again, you definitely would not have got the

above grid in front of you.

In the other possibility, you can think of the chain of events that would occur in case your

opponent chose to 'retain lower'.

The grid you would get in this case would be:

From the above case, your logical next step would be to retain right.

Thus, since we know that your second move is to retain right, it follows that your opponent's

first move is to 'retain lower'.

After this when you retain right, the numbers left in the grid would be:

Your opponent would again 'retain lower' in this case. Thus, he must have played 'retain lower' & 'retain lower'. Option (d) is correct.**Explanation :**There are two series intertwined in the given series.

F-J-N (skip 3 alphabets)

U-Q-M (skip 3 alphabets in the opposite order).

The next letter would depend on the second series above. After M, the 3 letters to be skipped

are L, K, J and hence 'I' should be the next letter in the series. Option (a) is correct**Explanation :**The numbers would be 1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 17, 19, 20, 21, 22, 23, 25, 27, 28,

29,31, 32, 34, 35, 37, 38, 39, 40, 41, 43, 44, 45, 47, 49, 50, 52, 53, 55, 57, 58 and 59.

There are 43 such numbers. Option (b) is correct.

Alternately, you could also have counted the numbers to be left out as: 6, 12, 18, 24, 30, ... 60

(10 numbers which are multiples of 6); and 15, 33, 51 (which have a sum of digits of 6); and

16, 26, 46 and 56 (numbers which have 6 in them). There are 17 numbers which have to be

left out from the 60 numbers. Hence, 43 numbers have to be counted. Option (b) is correct.**Explanation :**The flow would be:

Thus, Arun would be rowing twice.

Option (d) is correct**Explanation :**Collating the information you would get

that the family tree consists of the couples: A /br> (husband and doctor), E (Engineer and A's wife), D (husband), B (wife of husband). G being /br> the child of B-D and being a girl would be B & D's daughter. Similarly, F (girl) and C (boy) /br> would be A's and E children. Thus, C is A's son. Option (d) is correct.**Explanation :**The alphabet would be written as: AbCdEfGhIjKlMnOpQrStUvWxYz.

JULY would then be written as: jUlY.

Option (c) is correct.**Explanation :**48(x - y) = x

^{2}- y^{2}AE

48(x - y) = (x - y)(x + y) AE (x + y) = 48. Option (d) is correct.

**Ans . **

(d) Retain lower, retain lower

**Ans . **

(a) I

**Ans . **

(b) 43

**Ans . **

(d) Arun

**Ans . **

(d) A's son

**Ans . **

(c) jUlY

**Ans . **

(d) None of these

**Ans . **

(a) 2^{9}

**Explanation :**Income on day 1: = 2

^{0};

Income on day 2 = 2^{1};Income on day 3 = 2^{2}; Income on day 4 = 2^{3};

Thus, income on day 10 = 2^{9}. Option (a) is correct.

**Ans . **

(b) 79

**Explanation :**Solve this one through options.

For option (b) 79: First boy, sees 79 apples eats 1 apple and hides 26 apples and leaves 52 apples;

Second boy, sees 52 apples eats 1 apple and hides 17 apples and leaves 34 apples;

Third boy, sees 34 apples eats 1 apple and hides 11 apples and leaves 22 apples;

The final number is still one more than a multiple of 3.

Thus, option (b) satisfies all the conditions of the problem.

If you try the same with option (a) for instance you would get:

First boy, sees 67 apples eats 1 apple and hides 22 apples and leaves 44 apples;

This number is not one more than a multiple of 3. Hence, options (a) gets rejected.

If you try the same with option (c) for instance you would get:

First boy, sees 85 apples eats 1 apple and hides 28 apples and leaves 56 apples;

This number is not one more than a multiple of 3. Hence, options (c) gets rejected.

Option (b) is the correct answer.

**Directions for Questions 10 and 11:** Choose from these four diagrams the one that best illustrates
the relationship among three given classes.

**Explanation :**Reading the basic conditions should make you string a few logics together as follows:

1. Since Q is brighter than R, but is duller than the Don School student who is duller than P,

we have the order P > Q > R in terms of brightness of the Elite school students.

2. There is one Don school student who is brighter than A. Thus, A must be the second

brightest Don School student. Also, since the same Don School student is brighter than C,

we are talking about B. Thus, the Don School students in terms of brightness would be: B>A>C.

It is also known that B is duller than P. Thus we can move to answer the question.

P is the brightest as he is brighter than B (hence brighter than A and C) as well as brighter

than Q and R. Option (b) is correct**Explanation :**Reading the basic conditions should make you string a few logics together as follows:

1. Since Q is brighter than R, but is duller than the Don School student who is duller than P,

we have the order P > Q > R in terms of brightness of the Elite school students.

2. There is one Don school student who is brighter than A. Thus, A must be the second

brightest Don School student. Also, since the same Don School student is brighter than C,

we are talking about B. Thus, the Don School students in terms of brightness would be: B>A>C.

It is also known that B is duller than P. Thus we can move to answer the question.

R is the dullest amongst the Elite school students and the logic is explained in the explanation above.

**Ans . **

(b) P

**Ans . **

(c) R

**Directions for Questions 12 and 16:** Study the following example and answer the questions.

An electronic device rearranges numbers step-by-step in a particular order according to a set of
rules. The device stops when the final result is obtained. In this case the device stops at Step V.

**Explanation :**From the input to the output it is clear that

the electronic device just arranges all the numbers in a

decreasing order. It does so by progressively getting the left most numbers in the sequence in the

correct order. Based on this understanding you can move on to solve the questions.

Input: 09, 25, 16, 30, 32, 18, 17, 06

Step I: 32, 09, 25, 16, 30, 18, 17, 06

Step II: 32, 30, 09, 25, 16, 18, 17, 06

Step III: 32, 30, 25, 09, 16, 18, 17, 06

Option (d) matches with this third step.

Hence, option (d) is correct**Explanation :**Input: 16, 09, 25, 27, 06, 05

Step I: 27, 16, 09, 25, 06, 05

Step II: 27, 25, 16, 09, 06, 05

Option (a) is correct**Explanation :**Input: 25, 08, 35, 11, 88, 67, 23

Step I: 88, 25, 08, 35, 11, 67, 23

Step II: 88, 67, 25, 08, 35, 11, 23

Step III: 88, 67, 35, 25, 08, 11, 23 Step IV: 88, 67, 35, 25, 23, 08, 11

Step V: 88, 67, 35, 25, 23, 11, 08

Option (a) is correct**Explanation :**Input: 03, 31, 43, 22, 11, 09

Step I: 43, 03, 31, 22, 11, 09

Step II: 43, 31, 03, 22, 11, 09

Step III: 43, 31, 22, 03, 11, 09

Step IV: 43, 31, 22, 11, 03, 09

Step V: 43, 31, 22, 11, 09, 03

Thus, step V is the final step. Option (d) is the correct answer**Explanation :**It is not possible to determine a unique

input in such situations as there are multiple inputs that

are possible which can give you Step IV as described. In fact, if you check the options

themselves, you can see that both option (b) and option (c) give you Step IV as described by

the question.

Hence, option (d) is correct.

**Ans . **

(d) 32 30 25 09 16 18 17 06

**Ans . **

(a) Step II

**Ans . **

(a) 88 67 35 25 23 11 08

**Ans . **

(d) None of the above

**Ans . **

(d) None of the above

**Directions for Questions 17 and 18:** Read the following information carefully and then answer the
questions given below.

P # Q means P is the father of Q

P + Q means P is the mother of Q

P - Q means P is the brother of Q

P * Q means P is the sister of Q

**Explanation :**A + B # C - D Converts to A is the Mother of B,

B is the father of C, C is the brother of D.

Thus, A is D's grandmother. Option (c) is correct.**Explanation :**The relationship shown in option (b) converts to:

A is the sister of B, B is the father of C, C is

the sister of D and D is the brother of E. This means that C, D and E are siblings as they are

all children of B. Further, since A is the sister of B (C, D and E's father), it naturally follows

that A is the aunt of E. Thus, option (b) is the correct answer.

**Ans . **

(c) Grandmother

**Ans . **

(b) A*B # C*D - E