Puzzle Test
Directions for Questions 1 to 5:
Six friends A, B, C, D, E, and F work in different companies
namely—Pentasoft, Quark, Raymond’s, Sunmet, Trump & Gates and Udupi, and each wears different
coloured, company-sponsored shirts, viz., blue, green, pink, yellow, purple and red though not
necessarily in the same order.
i. The one wearing the blue shirt works in Sunmet and the one wearing a green shirt works in
Pentasoft.
ii. F does not work in Raymond’s or Trump and Gates.
iii. A wears pink shirt and works in Quark.
iv. D does not work in Trump & Gates and purple coloured shirt is not sponsored by Raymond’s.
v. E works in Udupi and neither D nor B works in Sunmet.
vi. Trump & Gates does not sponsor purple or yellow coloured shirts and C works in Pentasoft.
Ans .
a
- Explanation :
The direct clues give you the following linkages—green – Pentasoft, Blue– Sunmet A– Pink – Quark, E – Udupi, C – Pentasoft Combining these clues will give you the following table:
A B C D E F Quark Pentasoft Udupi Pink Green
At this point use Clue no. (ii) [about F]. This will give you that the correct pairing for Sunmet is with F. Also use Clue (iv) at this stage. The table would evolve to:
A B C D E F Quark Trump & Gates Pentasoft Raymonds Udupi Sunmet Pink Green Blue
A B C D E F Quark Trump & Gates Pentasoft Raymonds Udupi Sunmet Pink Red Green Yellow Purple Blue
From this point, you need to just read off the respective answers to the questions asked from the completed table.
Yellow. Option (a)
Ans .
b
- Explanation :
The direct clues give you the following linkages—green – Pentasoft, Blue– Sunmet A– Pink – Quark, E – Udupi, C – Pentasoft Combining these clues will give you the following table:
A B C D E F Quark Pentasoft Udupi Pink Green
At this point use Clue no. (ii) [about F]. This will give you that the correct pairing for Sunmet is with F. Also use Clue (iv) at this stage. The table would evolve to:
A B C D E F Quark Trump & Gates Pentasoft Raymonds Udupi Sunmet Pink Green Blue
A B C D E F Quark Trump & Gates Pentasoft Raymonds Udupi Sunmet Pink Red Green Yellow Purple Blue
From this point, you need to just read off the respective answers to the questions asked from the completed table.
Option (b) is correct.
Ans .
d
- Explanation :
The direct clues give you the following linkages—green – Pentasoft, Blue– Sunmet A– Pink – Quark, E – Udupi, C – Pentasoft Combining these clues will give you the following table:
A B C D E F Quark Pentasoft Udupi Pink Green
At this point use Clue no. (ii) [about F]. This will give you that the correct pairing for Sunmet is with F. Also use Clue (iv) at this stage. The table would evolve to:
A B C D E F Quark Trump & Gates Pentasoft Raymonds Udupi Sunmet Pink Green Blue
A B C D E F Quark Trump & Gates Pentasoft Raymonds Udupi Sunmet Pink Red Green Yellow Purple Blue
From this point, you need to just read off the respective answers to the questions asked from the completed table.
Option (d) is correct.
Ans .
c
- Explanation :
The direct clues give you the following linkages—green – Pentasoft, Blue– Sunmet A– Pink – Quark, E – Udupi, C – Pentasoft Combining these clues will give you the following table:
A B C D E F Quark Pentasoft Udupi Pink Green
At this point use Clue no. (ii) [about F]. This will give you that the correct pairing for Sunmet is with F. Also use Clue (iv) at this stage. The table would evolve to:
A B C D E F Quark Trump & Gates Pentasoft Raymonds Udupi Sunmet Pink Green Blue
A B C D E F Quark Trump & Gates Pentasoft Raymonds Udupi Sunmet Pink Red Green Yellow Purple Blue
From this point, you need to just read off the respective answers to the questions asked from the completed table.
Option (c) is correct.
Ans .
a
- Explanation :
The direct clues give you the following linkages—green – Pentasoft, Blue– Sunmet A– Pink – Quark, E – Udupi, C – Pentasoft Combining these clues will give you the following table:
A B C D E F Quark Pentasoft Udupi Pink Green
At this point use Clue no. (ii) [about F]. This will give you that the correct pairing for Sunmet is with F. Also use Clue (iv) at this stage. The table would evolve to:
A B C D E F Quark Trump & Gates Pentasoft Raymonds Udupi Sunmet Pink Green Blue
A B C D E F Quark Trump & Gates Pentasoft Raymonds Udupi Sunmet Pink Red Green Yellow Purple Blue
From this point, you need to just read off the respective answers to the questions asked from the completed table.
Option (a) is correct.
Directions for Questions 6 to 8:
(i) Five friends Amar, Kapil, Sarvesh, Rohan, and Nagesh wear trousers of different colours—
red, yellow, blue, white and green (not necessarily in this order).
(ii) Each one of them has different likings, viz., reading, playing, travelling, singing and writing.
(iii) Kapil, who has a liking for singing does not wear yellow trousers. Sarvesh wears red trousers
and does not like reading or writing. Nagesh likes to play and does not wear blue or yellow
trousers. Amar has liking for writing and Rohan does not wear yellow or green trousers.
Ans .
d
- Explanation :
Reaction Clue 1 5 People and 5 Trouser Colours Clue 2 5 Different Likings Clue 3 Statement 1 Kapil-Sing-Not Yellow Statement 2 Sarvesh – Red–Not Read or Write Statement 3 Nagesh – Play – Not Blue or Yellow Statement 4 Amar–Write Rohan – Not Yellow or Green
At this stage, combining Statements 1, 2, 3 and 4 of Clue (iii) you will get the following table:
Write Sing Travel* Read * Play Yellow# Blue/White/ Blue/ White/ Green White Green
* Since Sarvesh does not read, Rohan must like reading and Sarvesh must like travelling. # Amar must be yellow, since Kapil, Rohan and Nagesh are not yellow. Further we are not able to define the exact colours of Kapil, (who can be blue/white or green), Rohan (blue or white) or Nagesh (white/green). Hence the above table is the final one. Thus, Kapil’s trouser colours cannot be answered. (Question 6) Sarvesh likes travel (Question 7) and Amar–yellow–write is the correct combination.
Option (d)
Ans .
b
- Explanation :
Reaction Clue 1 5 People and 5 Trouser Colours Clue 2 5 Different Likings Clue 3 Statement 1 Kapil-Sing-Not Yellow Statement 2 Sarvesh – Red–Not Read or Write Statement 3 Nagesh – Play – Not Blue or Yellow Statement 4 Amar–Write Rohan – Not Yellow or Green
At this stage, combining Statements 1, 2, 3 and 4 of Clue (iii) you will get the following table:
Write Sing Travel* Read * Play Yellow# Blue/White/ Blue/ White/ Green White Green
* Since Sarvesh does not read, Rohan must like reading and Sarvesh must like travelling. # Amar must be yellow, since Kapil, Rohan and Nagesh are not yellow. Further we are not able to define the exact colours of Kapil, (who can be blue/white or green), Rohan (blue or white) or Nagesh (white/green). Hence the above table is the final one. Thus, Kapil’s trouser colours cannot be answered. (Question 6) Sarvesh likes travel (Question 7) and Amar–yellow–write is the correct combination.
Option (b)
Ans .
c
- Explanation :
Reaction Clue 1 5 People and 5 Trouser Colours Clue 2 5 Different Likings Clue 3 Statement 1 Kapil-Sing-Not Yellow Statement 2 Sarvesh – Red–Not Read or Write Statement 3 Nagesh – Play – Not Blue or Yellow Statement 4 Amar–Write Rohan – Not Yellow or Green
At this stage, combining Statements 1, 2, 3 and 4 of Clue (iii) you will get the following table:
Write Sing Travel* Read * Play Yellow# Blue/White/ Blue/ White/ Green White Green
* Since Sarvesh does not read, Rohan must like reading and Sarvesh must like travelling. # Amar must be yellow, since Kapil, Rohan and Nagesh are not yellow. Further we are not able to define the exact colours of Kapil, (who can be blue/white or green), Rohan (blue or white) or Nagesh (white/green). Hence the above table is the final one. Thus, Kapil’s trouser colours cannot be answered. (Question 6) Sarvesh likes travel (Question 7) and Amar–yellow–write is the correct combination.
Option (c)
Directions for Question 9 to 11:
i. Five students—Sujit, Randhir, Neena, Mihir, and Vinay have total five books on subjects—
Physics, Chemistry, Maths, Biology and English written by authors Gupta, Khanna, Harish,
Sharma and Edwin. Each student has only one book on one of the five subjects.
ii. Gupta is the author of the Physics book which is not owned by Vinay or Sujit. Mihir owns the
book written by Edwin.
iii. Neena owns the Maths book. Vinay has the English book which is not written by Khanna. The
Biology book is written by Sharma.
Ans .
d
- Explanation :
Reaction Clue 1 5 students, 5 books and 5 authorsClue 2 Statement 1 Gupta – Physics – Not Vinay or Sujt Statement 2 Edwin–Mihirj Clue 3 Statement 1 Maths –Neena Statement 2 English – Vinay–not Khanna Statement 3 Sharma – Biology
Sharma – BiologyOn the basis of the reaction to Clue (ii) and (iii) as shown above, you should realise that the maximum numbers of direct links are between the author and the subject. Hence, your solution table should first give a structural placement of authors and subjects. When you do so, the following table shall emerge.
Sharma Edwin Gupta Biology Physics Maths English Mihir Mihir Vinay
Reacting to the above the table, you will immediately see that Edwin must be Chemistry. Further using Sentence (ii) of Clue (iii) you will get that since Vinay is not using a book authored by Khanna, he must be using Harish and consequently Khanna must have authored Maths. We also know from Clue (ii), Sentence 1 that Gupta and Physics is not owned by Vinay or Sujit. Hence, Sujit must be Biology and Randhir must be Physics. The final table then becomes:
Consequently the correct answers is: Biology–Sujit–SharmaSharma Edwin Gupta Khanna Harish Biology Chemistry Physics Maths English Sujit Mihir Mihir Neena Vinay
Ans .
b
- Explanation :
Reaction Clue 1 5 students, 5 books and 5 authorsClue 2 Statement 1 Gupta – Physics – Not Vinay or Sujt Statement 2 Edwin–Mihirj Clue 3 Statement 1 Maths –Neena Statement 2 English – Vinay–not Khanna Statement 3 Sharma – Biology
Sharma – BiologyOn the basis of the reaction to Clue (ii) and (iii) as shown above, you should realise that the maximum numbers of direct links are between the author and the subject. Hence, your solution table should first give a structural placement of authors and subjects. When you do so, the following table shall emerge.
Sharma Edwin Gupta Biology Physics Maths English Mihir Mihir Vinay
Reacting to the above the table, you will immediately see that Edwin must be Chemistry. Further using Sentence (ii) of Clue (iii) you will get that since Vinay is not using a book authored by Khanna, he must be using Harish and consequently Khanna must have authored Maths. We also know from Clue (ii), Sentence 1 that Gupta and Physics is not owned by Vinay or Sujit. Hence, Sujit must be Biology and Randhir must be Physics. The final table then becomes:
Consequently the correct answers is: EdwinSharma Edwin Gupta Khanna Harish Biology Chemistry Physics Maths English Sujit Mihir Mihir Neena Vinay
Ans .
b
- Explanation :
Reaction Clue 1 5 students, 5 books and 5 authorsClue 2 Statement 1 Gupta – Physics – Not Vinay or Sujt Statement 2 Edwin–Mihirj Clue 3 Statement 1 Maths –Neena Statement 2 English – Vinay–not Khanna Statement 3 Sharma – Biology
Sharma – BiologyOn the basis of the reaction to Clue (ii) and (iii) as shown above, you should realise that the maximum numbers of direct links are between the author and the subject. Hence, your solution table should first give a structural placement of authors and subjects. When you do so, the following table shall emerge.
Sharma Edwin Gupta Biology Physics Maths English Mihir Mihir Vinay
Reacting to the above the table, you will immediately see that Edwin must be Chemistry. Further using Sentence (ii) of Clue (iii) you will get that since Vinay is not using a book authored by Khanna, he must be using Harish and consequently Khanna must have authored Maths. We also know from Clue (ii), Sentence 1 that Gupta and Physics is not owned by Vinay or Sujit. Hence, Sujit must be Biology and Randhir must be Physics. The final table then becomes:
Consequently the correct answers is: VinaySharma Edwin Gupta Khanna Harish Biology Chemistry Physics Maths English Sujit Mihir Mihir Neena Vinay
Directions for Questions 12 to 15:
i. Seven friends A, B, C, D, E, F and G are in Patna to attend a seminar at Mindworkzz. Five of
them have to go back to five different places—Delhi, Chennai, Lucknow, Bangalore, and
Kolkata.
ii. Five of them are executives, each specialising in Administration, Human Resource
Management (HRM), Marketing, Systems and Finance.
iii. E, an executive is going to Chennai, is neither from Finance nor Marketing. G is a system
specialist and is leaving for Delhi. F is an executive but is not going to one of the five places.
iv. B is an executive from HRM but has come at the airport to see off his friends.A is an
executive but not from Marketing and is flying to one of the destinations but not to Bangalore
or Kolkata.
Ans .
b
- Explanation :
From Clues (i), (ii), and (iii): 7 people–A, B, C, D, E, F & G 5 cities – Delhi, Chennai, Lucknow, Bangalore and Kolkata 5 specialisations – Admin, HRM, Marketing, Systems, Finance From Clues (iii) and (iv) we have:
D E – Chennai X Fin, X Marketing G – Delhi Systems F – No place ? B – No place HRM A – X Bangalore, X Kolkata X Marketing C -
Refining the above table, the following deduction can be made: E must be from Admin. The table evolves to:
D E – Chennai Admin G – Delhi Systems F – No place Marketing B – No place HRM A – Lucknow Finance C -
(b)
Ans .
c
- Explanation :
From Clues (i), (ii), and (iii): 7 people–A, B, C, D, E, F & G 5 cities – Delhi, Chennai, Lucknow, Bangalore and Kolkata 5 specialisations – Admin, HRM, Marketing, Systems, Finance From Clues (iii) and (iv) we have:
D E – Chennai X Fin, X Marketing G – Delhi Systems F – No place ? B – No place HRM A – X Bangalore, X Kolkata X Marketing C -
Refining the above table, the following deduction can be made: E must be from Admin. The table evolves to:
D E – Chennai Admin G – Delhi Systems F – No place Marketing B – No place HRM A – Lucknow Finance C -
(c)
Ans .
d
- Explanation :
From Clues (i), (ii), and (iii): 7 people–A, B, C, D, E, F & G 5 cities – Delhi, Chennai, Lucknow, Bangalore and Kolkata 5 specialisations – Admin, HRM, Marketing, Systems, Finance From Clues (iii) and (iv) we have:
D E – Chennai X Fin, X Marketing G – Delhi Systems F – No place ? B – No place HRM A – X Bangalore, X Kolkata X Marketing C -
Refining the above table, the following deduction can be made: E must be from Admin. The table evolves to:
D E – Chennai Admin G – Delhi Systems F – No place Marketing B – No place HRM A – Lucknow Finance C -
(d)
Ans .
d
- Explanation :
From Clues (i), (ii), and (iii): 7 people–A, B, C, D, E, F & G 5 cities – Delhi, Chennai, Lucknow, Bangalore and Kolkata 5 specialisations – Admin, HRM, Marketing, Systems, Finance From Clues (iii) and (iv) we have:
D E – Chennai X Fin, X Marketing G – Delhi Systems F – No place ? B – No place HRM A – X Bangalore, X Kolkata X Marketing C -
Refining the above table, the following deduction can be made: E must be from Admin. The table evolves to:
D E – Chennai Admin G – Delhi Systems F – No place Marketing B – No place HRM A – Lucknow Finance C -
(d)
Direction for Questions 16 to 20:
P, Q, R, S, T, U, and V are seven persons who travel to office
everyday in a particular train which stops at five stations—Andheri, Bandra, Vile-Parle, Elphinston
and Chinchpokli res-pectively— after it leaves the base station.
i. Three among them get in the train at the base station.
ii. S gets down at the station next to the station at which U gets down.
iii. Q does not get down either with P or T.
iv. V alone gets in at Vile-Parle and gets down with R after having passed one station.
v. P travels between only two consecutive stations and gets down at Chinchpokli.
vi. None of them gets in at Bandra.
vii. R gets in with U but does not get in with either Q or S.
viii. T gets in with two others and gets down alone after S.
ix. Q and S work in the same office and they get down together at Vile-Parle.
x. None of them gets down at Andheri.
Ans .
c
- Explanation :
Station Gets in Gets down Base Station T RU/QS __________ Andheri QS/RU __________ Bandra U Vile-Parle V QS Elphinston P T Chinchpokli VRP
Start from the Statement (iv). Then go through statement (v): P travels only two stations and gets down at Chinchpokli which means that he must have boarded at Elphinston. Then go to Statement (ix), proceed through (viii) to Statement (ii) and proceed as said in the remaining statements.
Ans .
d
- Explanation :
Station Gets in Gets down Base Station T RU/QS __________ Andheri QS/RU __________ Bandra U Vile-Parle V QS Elphinston P T Chinchpokli VRP
Start from the Statement (iv). Then go through statement (v): P travels only two stations and gets down at Chinchpokli which means that he must have boarded at Elphinston. Then go to Statement (ix), proceed through (viii) to Statement (ii) and proceed as said in the remaining statements.
Ans .
d
- Explanation :
Station Gets in Gets down Base Station T RU/QS __________ Andheri QS/RU __________ Bandra U Vile-Parle V QS Elphinston P T Chinchpokli VRP
Start from the Statement (iv). Then go through statement (v): P travels only two stations and gets down at Chinchpokli which means that he must have boarded at Elphinston. Then go to Statement (ix), proceed through (viii) to Statement (ii) and proceed as said in the remaining statements.
Ans .
c
- Explanation :
Station Gets in Gets down Base Station T RU/QS __________ Andheri QS/RU __________ Bandra U Vile-Parle V QS Elphinston P T Chinchpokli VRP
Start from the Statement (iv). Then go through statement (v): P travels only two stations and gets down at Chinchpokli which means that he must have boarded at Elphinston. Then go to Statement (ix), proceed through (viii) to Statement (ii) and proceed as said in the remaining statements.
Ans .
c
- Explanation :
Station Gets in Gets down Base Station T RU/QS __________ Andheri QS/RU __________ Bandra U Vile-Parle V QS Elphinston P T Chinchpokli VRP
Start from the Statement (iv). Then go through statement (v): P travels only two stations and gets down at Chinchpokli which means that he must have boarded at Elphinston. Then go to Statement (ix), proceed through (viii) to Statement (ii) and proceed as said in the remaining statements.
Directions for Questions 21 to 24:
Five friends went to an exhibition. At a shooting stall there are
three things to be shot at— balloons, coins and needles. The number of balloons shot are 1, 4, 5, 6
and 8, while the number of coins shot are 0, 1, 2, 4 and 6.
i. The number of coins shot by A is three times the number of coins shot by the person who shot
4 balloons.
ii. Three persons, including the one who shot four coins, did not shoot any needle.
iii. B did not shoot any needle.
iv. The one who shot one balloon did not shoot any needle or coin. Further he was not (c).
v. D shot balloons and coins but no needle.
vi. C who did not shoot any needle, shot half as many coins as the person who shot twice as many
balloons as he did.
vii. E shot two more balloons than A, but A shot two more coins than E.
Ans .
c
- Explanation :
Option (c) is true for A. Hence (c).
Ans .
a
- Explanation :
D shot 5 balloons is true. Hence Option (a) is correct.
Ans .
c
- Explanation :
Option (c) is again correct from the table.
Ans .
a
- Explanation :
A. Hence Option (a) is correct.
Directions for Questions 25 and 26:
The jailor of XYZ jail had 6 fruits—3 oranges, 2 apples and
one pineapple. Four prisoners—101, 102, 103 and 104 are lined up one behind the other; the jailor
helps them put the fruit on their head so that they cannot see the fruit kept on their head. Prisoner
number 101 can see the fruit kept on the heads of 102, 103 and 104. Prisoner number 102 can see the
fruit kept on 103’s and 104’s head. 103 can see the fruit kept on 104’s head. 104 cannot see any of the
fruits since he is at the front of the line.
Now, the jailor asks the prisoners to tell the name of the fruit kept on their head. Neither of them
could reply.
Ans .
a
- Explanation :
The following 19 possibilities emerge for what 101 could have seen. (Note: Be systematic while making this table.)
Possibility # 104 103 102 1 O O O 2 O O A 3 O O P 4 O A O 5 O P O 6 A O O 7 P O O 8 A A O 9 A O A 10 O A A 11 O A P 12 O P A 13 P O A 14 A O P 15 O A P 16 O P A 17 A A P 18 A P A 19 P A A
From the table above it is clear that if 101 had seen 2 apples and 1 pineapple he would have answered immediately. But since he doesn’t answer, possibilities 17, 18 or 19 can be ruled out. 102 also realises that 101 is not answering and hence rules out possibilities 17, 18 and 19. He considers what he sees on 103 and 104 in the context of possibilities 1–16. It can be seen from the table that if he had seen 2 apples, he would know that there was only Possibility 8 to consider. In such a case he would know that there was definitely an orange on his head. However, he does not answer. Thus, we can conclude that Possibility 8 is not possible. 103 realises that 102 is not answering and considers only possibilities 1–7 and 9–16. Of these, we can realise that if he had seen an apple or a pineapple on 104 he would know that he had an orange on his head. But, since he doesn’t answer, we can eliminate Possibilities 6, 7, 9, 13 and 14. This leaves us with only Possibilities 1–5, 10–12 and 15–16. Hence: (a) 104 must have an orange on his head.
Ans .
d
- Explanation :
The following 19 possibilities emerge for what 101 could have seen. (Note: Be systematic while making this table.)
Possibility # 104 103 102 1 O O O 2 O O A 3 O O P 4 O A O 5 O P O 6 A O O 7 P O O 8 A A O 9 A O A 10 O A A 11 O A P 12 O P A 13 P O A 14 A O P 15 O A P 16 O P A 17 A A P 18 A P A 19 P A A
From the table above it is clear that if 101 had seen 2 apples and 1 pineapple he would have answered immediately. But since he doesn’t answer, possibilities 17, 18 or 19 can be ruled out. 102 also realises that 101 is not answering and hence rules out possibilities 17, 18 and 19. He considers what he sees on 103 and 104 in the context of possibilities 1–16. It can be seen from the table that if he had seen 2 apples, he would know that there was only Possibility 8 to consider. In such a case he would know that there was definitely an orange on his head. However, he does not answer. Thus, we can conclude that Possibility 8 is not possible. 103 realises that 102 is not answering and considers only possibilities 1–7 and 9–16. Of these, we can realise that if he had seen an apple or a pineapple on 104 he would know that he had an orange on his head. But, since he doesn’t answer, we can eliminate Possibilities 6, 7, 9, 13 and 14. This leaves us with only Possibilities 1–5, 10–12 and 15–16. Hence:(d) All statements are true.
Directions for Questions 27 and 31:
Four couples decided to play Holi. Each couple used three
different colours. No two couples used the same combination of colours.
Asha, Bhavna, Chanchal and Divya are females whereas Pradeep, Qartar, Rajeev and Sanjay are
males.
The colours they use are red, green, yellow and black.
i. Chanchal, who is not the wife of Sanjay, used red colour.
ii. Pradeep’s wife used yellow and black colours but Qartar’s wife used only one of these
colours.
iii. Asha is not the wife of Pradeep or Sanjay.
iv. Bhavna and Sanjay’s wife both used red and yellow colours.
Ans .
rghtopn
- Explanation :
Wives Husbands Colour Combinations Asha (A) Pradeep (P) (1) Red, Green, Yellow Bhavna (B) Qartar (Q) (2) Red, Green, Black Chanchal (C) Rajeev (R) (3) Red, Yellow, Black Divya (D) Sanjay (S) (4) Green, Yellow, Black
Using Clue (i) and Clue (iii), we can make some conclusions about Asha and Chanchal.
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna- Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya Sanjay 1/3 (4) Green, Yellow, Black
Using Clues (ii) and (iv), we get some conclusions about the men and the colour combination they used. (Note: We know Bhavna is not Sanjay’s wife because Clue (iv) mentions them as separate individuals).
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya Sanjay 1/3 (4) Green, Yellow, Black
From the above table (the wives column) it is clear that P, Q and R have to be shared amongst A, B and C in random order. Hence, Divya must be Sanjay’s wife. The table evolves to:
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
From the above table, it is evident that Color Combination 4 belongs to Asha (as Color Combinations 1/2/3 are shared between Bhavna, Chanchal and Divya). Also, Chanchal would get Color Combination 2 as it cannot go to any other woman. The table now becomes:
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
Asha- Q/R 4 Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
At this stage Clue (ii) gives us that Qartar’s wife used only one colour out of yellow and black. Hence, Asha (Color Combination 4) cannot be Qartar’s wife and thus must be Rajeev’s wife. This means that P and Q must be shared between B and C. Since we know that Pradeep’s wife used yellow and black colours, Chanchal cannot be married to Pradeep (Chanchal’s colour combination does not use both the colours yellow and black). Thus Pradeep must be married to Bhavana. Thus, the table evolves to:
A – R – (4)
B – P – (3)
C – Q – (2)
D – S – (1)
Accordingly the answers is: Rajeev (c)
Ans .
b
- Explanation :
Wives Husbands Colour Combinations Asha (A) Pradeep (P) (1) Red, Green, Yellow Bhavna (B) Qartar (Q) (2) Red, Green, Black Chanchal (C) Rajeev (R) (3) Red, Yellow, Black Divya (D) Sanjay (S) (4) Green, Yellow, Black
Using Clue (i) and Clue (iii), we can make some conclusions about Asha and Chanchal.
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna- Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya Sanjay 1/3 (4) Green, Yellow, Black
Using Clues (ii) and (iv), we get some conclusions about the men and the colour combination they used. (Note: We know Bhavna is not Sanjay’s wife because Clue (iv) mentions them as separate individuals).
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya Sanjay 1/3 (4) Green, Yellow, Black
From the above table (the wives column) it is clear that P, Q and R have to be shared amongst A, B and C in random order. Hence, Divya must be Sanjay’s wife. The table evolves to:
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
From the above table, it is evident that Color Combination 4 belongs to Asha (as Color Combinations 1/2/3 are shared between Bhavna, Chanchal and Divya). Also, Chanchal would get Color Combination 2 as it cannot go to any other woman. The table now becomes:
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
Asha- Q/R 4 Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
At this stage Clue (ii) gives us that Qartar’s wife used only one colour out of yellow and black. Hence, Asha (Color Combination 4) cannot be Qartar’s wife and thus must be Rajeev’s wife. This means that P and Q must be shared between B and C. Since we know that Pradeep’s wife used yellow and black colours, Chanchal cannot be married to Pradeep (Chanchal’s colour combination does not use both the colours yellow and black). Thus Pradeep must be married to Bhavana. Thus, the table evolves to:
A – R – (4)
B – P – (3)
C – Q – (2)
D – S – (1)
Accordingly the answers is: Chanchal (b)
Ans .
a
- Explanation :
Wives Husbands Colour Combinations Asha (A) Pradeep (P) (1) Red, Green, Yellow Bhavna (B) Qartar (Q) (2) Red, Green, Black Chanchal (C) Rajeev (R) (3) Red, Yellow, Black Divya (D) Sanjay (S) (4) Green, Yellow, Black
Using Clue (i) and Clue (iii), we can make some conclusions about Asha and Chanchal.
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna- Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya Sanjay 1/3 (4) Green, Yellow, Black
Using Clues (ii) and (iv), we get some conclusions about the men and the colour combination they used. (Note: We know Bhavna is not Sanjay’s wife because Clue (iv) mentions them as separate individuals).
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya Sanjay 1/3 (4) Green, Yellow, Black
From the above table (the wives column) it is clear that P, Q and R have to be shared amongst A, B and C in random order. Hence, Divya must be Sanjay’s wife. The table evolves to:
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
From the above table, it is evident that Color Combination 4 belongs to Asha (as Color Combinations 1/2/3 are shared between Bhavna, Chanchal and Divya). Also, Chanchal would get Color Combination 2 as it cannot go to any other woman. The table now becomes:
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
Asha- Q/R 4 Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
At this stage Clue (ii) gives us that Qartar’s wife used only one colour out of yellow and black. Hence, Asha (Color Combination 4) cannot be Qartar’s wife and thus must be Rajeev’s wife. This means that P and Q must be shared between B and C. Since we know that Pradeep’s wife used yellow and black colours, Chanchal cannot be married to Pradeep (Chanchal’s colour combination does not use both the colours yellow and black). Thus Pradeep must be married to Bhavana. Thus, the table evolves to:
A – R – (4)
B – P – (3)
C – Q – (2)
D – S – (1)
Accordingly the answers is: (a)
Ans .
c
- Explanation :
Wives Husbands Colour Combinations Asha (A) Pradeep (P) (1) Red, Green, Yellow Bhavna (B) Qartar (Q) (2) Red, Green, Black Chanchal (C) Rajeev (R) (3) Red, Yellow, Black Divya (D) Sanjay (S) (4) Green, Yellow, Black
Using Clue (i) and Clue (iii), we can make some conclusions about Asha and Chanchal.
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna- Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya Sanjay 1/3 (4) Green, Yellow, Black
Using Clues (ii) and (iv), we get some conclusions about the men and the colour combination they used. (Note: We know Bhavna is not Sanjay’s wife because Clue (iv) mentions them as separate individuals).
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya Sanjay 1/3 (4) Green, Yellow, Black
From the above table (the wives column) it is clear that P, Q and R have to be shared amongst A, B and C in random order. Hence, Divya must be Sanjay’s wife. The table evolves to:
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
From the above table, it is evident that Color Combination 4 belongs to Asha (as Color Combinations 1/2/3 are shared between Bhavna, Chanchal and Divya). Also, Chanchal would get Color Combination 2 as it cannot go to any other woman. The table now becomes:
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
Asha- Q/R 4 Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
At this stage Clue (ii) gives us that Qartar’s wife used only one colour out of yellow and black. Hence, Asha (Color Combination 4) cannot be Qartar’s wife and thus must be Rajeev’s wife. This means that P and Q must be shared between B and C. Since we know that Pradeep’s wife used yellow and black colours, Chanchal cannot be married to Pradeep (Chanchal’s colour combination does not use both the colours yellow and black). Thus Pradeep must be married to Bhavana. Thus, the table evolves to:
A – R – (4)
B – P – (3)
C – Q – (2)
D – S – (1)
Accordingly the answers is: (c)
Ans .
c
- Explanation :
Wives Husbands Colour Combinations Asha (A) Pradeep (P) (1) Red, Green, Yellow Bhavna (B) Qartar (Q) (2) Red, Green, Black Chanchal (C) Rajeev (R) (3) Red, Yellow, Black Divya (D) Sanjay (S) (4) Green, Yellow, Black
Using Clue (i) and Clue (iii), we can make some conclusions about Asha and Chanchal.
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna- Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya Sanjay 1/3 (4) Green, Yellow, Black
Using Clues (ii) and (iv), we get some conclusions about the men and the colour combination they used. (Note: We know Bhavna is not Sanjay’s wife because Clue (iv) mentions them as separate individuals).
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya Sanjay 1/3 (4) Green, Yellow, Black
From the above table (the wives column) it is clear that P, Q and R have to be shared amongst A, B and C in random order. Hence, Divya must be Sanjay’s wife. The table evolves to:
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
From the above table, it is evident that Color Combination 4 belongs to Asha (as Color Combinations 1/2/3 are shared between Bhavna, Chanchal and Divya). Also, Chanchal would get Color Combination 2 as it cannot go to any other woman. The table now becomes:
Asha- Q/R Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
Asha- Q/R 4 Pradeep 3/4 (1) Red, Green, Yellow Bhavna-P,Q,R,1/3 Qartar 1/2 (2) Red, Green, Black Chanchal- P/Q/R/1/2/3 Rajeev (3) Red, Yellow, Black Divya- S 1/3 Sanjay 1/3 (4) Green, Yellow, Black
At this stage Clue (ii) gives us that Qartar’s wife used only one colour out of yellow and black. Hence, Asha (Color Combination 4) cannot be Qartar’s wife and thus must be Rajeev’s wife. This means that P and Q must be shared between B and C. Since we know that Pradeep’s wife used yellow and black colours, Chanchal cannot be married to Pradeep (Chanchal’s colour combination does not use both the colours yellow and black). Thus Pradeep must be married to Bhavana. Thus, the table evolves to:
A – R – (4)
B – P – (3)
C – Q – (2)
D – S – (1)
Accordingly the answers is: (c)
Directions for Questions 32 to 36:
Abhay, Balbir, Chandan, Dinesh and Eklakh are alumni of the
IAS academy in Mussoorie. They are in Mussoorie to attend an alumni meet along with their wives
Priya, Quindal, Riya, Shailja and Tulsi, (not necessarily in the given order). They stay in the guest
room of the academy in rooms numbered from 101 to 105. One interesting thing is that each couple’s
wedding anniversary is on the coming Friday.
i. No two married couples were married in the same year.
ii. Balbir whose wife is not Shailja was married three fourths of as many years ago as Dinesh.
iii. Eklakh is staying in room number 103.
iv. Priya was married five years before Abhay and three years before Eklakh.
v. Only Shailja’s room is in-between Abhay’s and Eklakh’s room.
vi. Abhay, who was married before Shailja, was married five years after Chandan got married.
vii. The couple staying in room number 101 got married 10 years before the couple staying in
room 104.
viii. Quindal is staying in room number 102.
ix. Tulsi was married before Riya and she was married 12 years before Quindal got married.
Based on the above information, answer questions 32 to 36:
Ans .
b
- Explanation :
The initial grid to start off would be something like:
P Q R S T 101 102 103 104 105 A B C D E
The following deductions would follow: From Clues (ii), (iii), (iv) and (v) the grid would evolve to:
P Q R S T 101 102 103 104 105 A x x x B x x C x D x E x x x x √ x x
Besides, from these 4 clues we could also realise the following additional deductions: (a) Order of marriage P ->+3 E ->+2 A (From Clue iv) (b) Shailja must be in either 102 or 104. (c) Abhay’s room must be either 101 or 105. Using Clue (vi) we get that Shailja is not Abhay’s wife and neither is she Chandan’s wife. (Since Chandan was married before Abhay and Shailja was married after Abhay). Hence, she must be Dinesh’s wife. Also, Clue (viii) gives us that Quindal is in Room 102, hence from deduction (b) above Shailja must be in Room 104 and consequently Abhay must be in Room 105. The table would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x C x x x x D x x x √ x x x x √ x E x x x x x √ x x
Note: One additional deduction we have drawn in the above table is that Quindal (being in Room 102) cannot be the wife of either Abhay (105) or Eklakh (103). Hence R and T would be the wives of A and E (in random order) as they have to be shared between A and E. This also means that P and Q must be shared between B and C. Thus the grid evolves to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x x √ x x
At this point use Clue (ix), along with the deduction P ->+3 E ->+2 A Since Tulsi and Riya have to be shared between Abhay and Eklakh and Eklakh has got married before Abhay, he must be married to Tulsi and Abhay to Riya. The grid would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
At this stage if you try to draw a time line for their marriages, you would get the following figure: Existing figure Priya ->+3 Eklakh ->+2 Abhay If we use the logic contained in Clue (vi), we get that Abhay married 5 years after Chandan. Hence, Chandan and Priya must be married. Consequently Quindal and Balbir must be married. Also, since Balbir got married 3/4 th the number of years ago as Dinesh we can conclude that Balbir got married 15 years ago. Based on these deductions the timeline looks like:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x √ x x x x √ x x x C √ x x x x √ x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
The answer is:Abhay. Option (b) is correct.
Ans .
b
- Explanation :
The initial grid to start off would be something like:
P Q R S T 101 102 103 104 105 A B C D E
The following deductions would follow: From Clues (ii), (iii), (iv) and (v) the grid would evolve to:
P Q R S T 101 102 103 104 105 A x x x B x x C x D x E x x x x √ x x
Besides, from these 4 clues we could also realise the following additional deductions: (a) Order of marriage P ->+3 E ->+2 A (From Clue iv) (b) Shailja must be in either 102 or 104. (c) Abhay’s room must be either 101 or 105. Using Clue (vi) we get that Shailja is not Abhay’s wife and neither is she Chandan’s wife. (Since Chandan was married before Abhay and Shailja was married after Abhay). Hence, she must be Dinesh’s wife. Also, Clue (viii) gives us that Quindal is in Room 102, hence from deduction (b) above Shailja must be in Room 104 and consequently Abhay must be in Room 105. The table would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x C x x x x D x x x √ x x x x √ x E x x x x x √ x x
Note: One additional deduction we have drawn in the above table is that Quindal (being in Room 102) cannot be the wife of either Abhay (105) or Eklakh (103). Hence R and T would be the wives of A and E (in random order) as they have to be shared between A and E. This also means that P and Q must be shared between B and C. Thus the grid evolves to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x x √ x x
At this point use Clue (ix), along with the deduction P ->+3 E ->+2 A Since Tulsi and Riya have to be shared between Abhay and Eklakh and Eklakh has got married before Abhay, he must be married to Tulsi and Abhay to Riya. The grid would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
At this stage if you try to draw a time line for their marriages, you would get the following figure: Existing figure Priya ->+3 Eklakh ->+2 Abhay If we use the logic contained in Clue (vi), we get that Abhay married 5 years after Chandan. Hence, Chandan and Priya must be married. Consequently Quindal and Balbir must be married. Also, since Balbir got married 3/4 th the number of years ago as Dinesh we can conclude that Balbir got married 15 years ago. Based on these deductions the timeline looks like:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x √ x x x x √ x x x C √ x x x x √ x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
The answer is:
Ans .
b
- Explanation :
The initial grid to start off would be something like:
P Q R S T 101 102 103 104 105 A B C D E
The following deductions would follow: From Clues (ii), (iii), (iv) and (v) the grid would evolve to:
P Q R S T 101 102 103 104 105 A x x x B x x C x D x E x x x x √ x x
Besides, from these 4 clues we could also realise the following additional deductions: (a) Order of marriage P ->+3 E ->+2 A (From Clue iv) (b) Shailja must be in either 102 or 104. (c) Abhay’s room must be either 101 or 105. Using Clue (vi) we get that Shailja is not Abhay’s wife and neither is she Chandan’s wife. (Since Chandan was married before Abhay and Shailja was married after Abhay). Hence, she must be Dinesh’s wife. Also, Clue (viii) gives us that Quindal is in Room 102, hence from deduction (b) above Shailja must be in Room 104 and consequently Abhay must be in Room 105. The table would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x C x x x x D x x x √ x x x x √ x E x x x x x √ x x
Note: One additional deduction we have drawn in the above table is that Quindal (being in Room 102) cannot be the wife of either Abhay (105) or Eklakh (103). Hence R and T would be the wives of A and E (in random order) as they have to be shared between A and E. This also means that P and Q must be shared between B and C. Thus the grid evolves to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x x √ x x
At this point use Clue (ix), along with the deduction P ->+3 E ->+2 A Since Tulsi and Riya have to be shared between Abhay and Eklakh and Eklakh has got married before Abhay, he must be married to Tulsi and Abhay to Riya. The grid would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
At this stage if you try to draw a time line for their marriages, you would get the following figure: Existing figure Priya ->+3 Eklakh ->+2 Abhay If we use the logic contained in Clue (vi), we get that Abhay married 5 years after Chandan. Hence, Chandan and Priya must be married. Consequently Quindal and Balbir must be married. Also, since Balbir got married 3/4 th the number of years ago as Dinesh we can conclude that Balbir got married 15 years ago. Based on these deductions the timeline looks like:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x √ x x x x √ x x x C √ x x x x √ x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
The answer is:Quindal. Option (b) is correct.
Ans .
d
- Explanation :
The initial grid to start off would be something like:
P Q R S T 101 102 103 104 105 A B C D E
The following deductions would follow: From Clues (ii), (iii), (iv) and (v) the grid would evolve to:
P Q R S T 101 102 103 104 105 A x x x B x x C x D x E x x x x √ x x
Besides, from these 4 clues we could also realise the following additional deductions: (a) Order of marriage P ->+3 E ->+2 A (From Clue iv) (b) Shailja must be in either 102 or 104. (c) Abhay’s room must be either 101 or 105. Using Clue (vi) we get that Shailja is not Abhay’s wife and neither is she Chandan’s wife. (Since Chandan was married before Abhay and Shailja was married after Abhay). Hence, she must be Dinesh’s wife. Also, Clue (viii) gives us that Quindal is in Room 102, hence from deduction (b) above Shailja must be in Room 104 and consequently Abhay must be in Room 105. The table would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x C x x x x D x x x √ x x x x √ x E x x x x x √ x x
Note: One additional deduction we have drawn in the above table is that Quindal (being in Room 102) cannot be the wife of either Abhay (105) or Eklakh (103). Hence R and T would be the wives of A and E (in random order) as they have to be shared between A and E. This also means that P and Q must be shared between B and C. Thus the grid evolves to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x x √ x x
At this point use Clue (ix), along with the deduction P ->+3 E ->+2 A Since Tulsi and Riya have to be shared between Abhay and Eklakh and Eklakh has got married before Abhay, he must be married to Tulsi and Abhay to Riya. The grid would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
At this stage if you try to draw a time line for their marriages, you would get the following figure: Existing figure Priya ->+3 Eklakh ->+2 Abhay If we use the logic contained in Clue (vi), we get that Abhay married 5 years after Chandan. Hence, Chandan and Priya must be married. Consequently Quindal and Balbir must be married. Also, since Balbir got married 3/4 th the number of years ago as Dinesh we can conclude that Balbir got married 15 years ago. Based on these deductions the timeline looks like:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x √ x x x x √ x x x C √ x x x x √ x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
The answer is:All the rooms would need to shift. Option (d) is correct.
Ans .
b
- Explanation :
The initial grid to start off would be something like:
P Q R S T 101 102 103 104 105 A B C D E
The following deductions would follow: From Clues (ii), (iii), (iv) and (v) the grid would evolve to:
P Q R S T 101 102 103 104 105 A x x x B x x C x D x E x x x x √ x x
Besides, from these 4 clues we could also realise the following additional deductions: (a) Order of marriage P ->+3 E ->+2 A (From Clue iv) (b) Shailja must be in either 102 or 104. (c) Abhay’s room must be either 101 or 105. Using Clue (vi) we get that Shailja is not Abhay’s wife and neither is she Chandan’s wife. (Since Chandan was married before Abhay and Shailja was married after Abhay). Hence, she must be Dinesh’s wife. Also, Clue (viii) gives us that Quindal is in Room 102, hence from deduction (b) above Shailja must be in Room 104 and consequently Abhay must be in Room 105. The table would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x C x x x x D x x x √ x x x x √ x E x x x x x √ x x
Note: One additional deduction we have drawn in the above table is that Quindal (being in Room 102) cannot be the wife of either Abhay (105) or Eklakh (103). Hence R and T would be the wives of A and E (in random order) as they have to be shared between A and E. This also means that P and Q must be shared between B and C. Thus the grid evolves to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x x √ x x
At this point use Clue (ix), along with the deduction P ->+3 E ->+2 A Since Tulsi and Riya have to be shared between Abhay and Eklakh and Eklakh has got married before Abhay, he must be married to Tulsi and Abhay to Riya. The grid would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
At this stage if you try to draw a time line for their marriages, you would get the following figure: Existing figure Priya ->+3 Eklakh ->+2 Abhay If we use the logic contained in Clue (vi), we get that Abhay married 5 years after Chandan. Hence, Chandan and Priya must be married. Consequently Quindal and Balbir must be married. Also, since Balbir got married 3/4 th the number of years ago as Dinesh we can conclude that Balbir got married 15 years ago. Based on these deductions the timeline looks like:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x √ x x x x √ x x x C √ x x x x √ x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
The answer is:27 years. Option (b) is correct.
Ans .
a
- Explanation :
The initial grid to start off would be something like:
P Q R S T 101 102 103 104 105 A B C D E
The following deductions would follow: From Clues (ii), (iii), (iv) and (v) the grid would evolve to:
P Q R S T 101 102 103 104 105 A x x x B x x C x D x E x x x x √ x x
Besides, from these 4 clues we could also realise the following additional deductions: (a) Order of marriage P ->+3 E ->+2 A (From Clue iv) (b) Shailja must be in either 102 or 104. (c) Abhay’s room must be either 101 or 105. Using Clue (vi) we get that Shailja is not Abhay’s wife and neither is she Chandan’s wife. (Since Chandan was married before Abhay and Shailja was married after Abhay). Hence, she must be Dinesh’s wife. Also, Clue (viii) gives us that Quindal is in Room 102, hence from deduction (b) above Shailja must be in Room 104 and consequently Abhay must be in Room 105. The table would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x C x x x x D x x x √ x x x x √ x E x x x x x √ x x
Note: One additional deduction we have drawn in the above table is that Quindal (being in Room 102) cannot be the wife of either Abhay (105) or Eklakh (103). Hence R and T would be the wives of A and E (in random order) as they have to be shared between A and E. This also means that P and Q must be shared between B and C. Thus the grid evolves to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x x √ x x
At this point use Clue (ix), along with the deduction P ->+3 E ->+2 A Since Tulsi and Riya have to be shared between Abhay and Eklakh and Eklakh has got married before Abhay, he must be married to Tulsi and Abhay to Riya. The grid would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
At this stage if you try to draw a time line for their marriages, you would get the following figure: Existing figure Priya ->+3 Eklakh ->+2 Abhay If we use the logic contained in Clue (vi), we get that Abhay married 5 years after Chandan. Hence, Chandan and Priya must be married. Consequently Quindal and Balbir must be married. Also, since Balbir got married 3/4 th the number of years ago as Dinesh we can conclude that Balbir got married 15 years ago. Based on these deductions the timeline looks like:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x √ x x x x √ x x x C √ x x x x √ x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
The answer is:We have two possible combinations.
But from both combinations we get that X lives in the blue house. Option (a) is correct.
Ans .
b
- Explanation :
The initial grid to start off would be something like:
P Q R S T 101 102 103 104 105 A B C D E
The following deductions would follow: From Clues (ii), (iii), (iv) and (v) the grid would evolve to:
P Q R S T 101 102 103 104 105 A x x x B x x C x D x E x x x x √ x x
Besides, from these 4 clues we could also realise the following additional deductions: (a) Order of marriage P ->+3 E ->+2 A (From Clue iv) (b) Shailja must be in either 102 or 104. (c) Abhay’s room must be either 101 or 105. Using Clue (vi) we get that Shailja is not Abhay’s wife and neither is she Chandan’s wife. (Since Chandan was married before Abhay and Shailja was married after Abhay). Hence, she must be Dinesh’s wife. Also, Clue (viii) gives us that Quindal is in Room 102, hence from deduction (b) above Shailja must be in Room 104 and consequently Abhay must be in Room 105. The table would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x C x x x x D x x x √ x x x x √ x E x x x x x √ x x
Note: One additional deduction we have drawn in the above table is that Quindal (being in Room 102) cannot be the wife of either Abhay (105) or Eklakh (103). Hence R and T would be the wives of A and E (in random order) as they have to be shared between A and E. This also means that P and Q must be shared between B and C. Thus the grid evolves to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x x √ x x
At this point use Clue (ix), along with the deduction P ->+3 E ->+2 A Since Tulsi and Riya have to be shared between Abhay and Eklakh and Eklakh has got married before Abhay, he must be married to Tulsi and Abhay to Riya. The grid would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
At this stage if you try to draw a time line for their marriages, you would get the following figure: Existing figure Priya ->+3 Eklakh ->+2 Abhay If we use the logic contained in Clue (vi), we get that Abhay married 5 years after Chandan. Hence, Chandan and Priya must be married. Consequently Quindal and Balbir must be married. Also, since Balbir got married 3/4 th the number of years ago as Dinesh we can conclude that Balbir got married 15 years ago. Based on these deductions the timeline looks like:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x √ x x x x √ x x x C √ x x x x √ x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
The answer is:M would live in a palace as U,T and P like either black or blue and X lives in a hotel. Option (b) is correct.
Ans .
rghtopn
- Explanation :
The initial grid to start off would be something like:
P Q R S T 101 102 103 104 105 A B C D E
The following deductions would follow: From Clues (ii), (iii), (iv) and (v) the grid would evolve to:
P Q R S T 101 102 103 104 105 A x x x B x x C x D x E x x x x √ x x
Besides, from these 4 clues we could also realise the following additional deductions: (a) Order of marriage P ->+3 E ->+2 A (From Clue iv) (b) Shailja must be in either 102 or 104. (c) Abhay’s room must be either 101 or 105. Using Clue (vi) we get that Shailja is not Abhay’s wife and neither is she Chandan’s wife. (Since Chandan was married before Abhay and Shailja was married after Abhay). Hence, she must be Dinesh’s wife. Also, Clue (viii) gives us that Quindal is in Room 102, hence from deduction (b) above Shailja must be in Room 104 and consequently Abhay must be in Room 105. The table would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x C x x x x D x x x √ x x x x √ x E x x x x x √ x x
Note: One additional deduction we have drawn in the above table is that Quindal (being in Room 102) cannot be the wife of either Abhay (105) or Eklakh (103). Hence R and T would be the wives of A and E (in random order) as they have to be shared between A and E. This also means that P and Q must be shared between B and C. Thus the grid evolves to:
P Q(102) R S(104) T 101 102 103 104 105 A x x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x x √ x x
At this point use Clue (ix), along with the deduction P ->+3 E ->+2 A Since Tulsi and Riya have to be shared between Abhay and Eklakh and Eklakh has got married before Abhay, he must be married to Tulsi and Abhay to Riya. The grid would evolve to:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x x x x x x C x x x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
At this stage if you try to draw a time line for their marriages, you would get the following figure: Existing figure Priya ->+3 Eklakh ->+2 Abhay If we use the logic contained in Clue (vi), we get that Abhay married 5 years after Chandan. Hence, Chandan and Priya must be married. Consequently Quindal and Balbir must be married. Also, since Balbir got married 3/4 th the number of years ago as Dinesh we can conclude that Balbir got married 15 years ago. Based on these deductions the timeline looks like:
P Q(102) R S(104) T 101 102 103 104 105 A x x √ x x x x x xx √ B x √ x x x x √ x x x C √ x x x x √ x x x x D x x x √ x x x x √ x E x x x x √ x x √ x x
The answer is: The grid would be:12 1 2 Sharma’s Pattabhiraman Banerjee White Blue Red Sambar Fried Brinjal Makkai-ki-roti
Option (c) is correct.
Directions for Questions 40 to 41:
Read the information and answer the questions.
Amitabh, Bhagyashree, Chunky, Dharmendra, Ekta, Farhan and Govinda are students of a class. Each
of them has a different favourite subject, viz., Economics, Commerce, Zoology, Sociology, Statistics,
Urdu and Computers but not necessarily in the same order. There are two such students whose one
sister each is there in the group. There is no other relation among the students. No boy likes
Commerce or Urdu. Dharmendra, who does not like Sociology and Statistics, is the brother of that
student who likes Computers. The student who likes Sociology is the sister of that boy student who
likes Economics. F is a boy student, B is sister of A.
Ans .
d
- Explanation :
Let us tabulate the given information to get a clear picture of the scenario. The first piece of information that fills the blanks is that no boy likes Commerce or Urdu. Then next information that is useful is that Dharmendra does not prefer Sociology and Statistics and is a boy hence he does not like Urdu and Commerce also. He is also brother of the person who opts for Computers. (Thus the person opting for computers must be a girl). So he must be having either Economics or Zoology. Now we are given that Amitabh and Bhagyashree are brother and sister and, hence Amitabh and Bhagyashree both will not have computers. Also Farhan is given as a boy student hence, by default from previous information, he does not like Urdu and Commerce, and also since he is a boy he cannot be Dharmendra’s sister and thus cannot have computers. Thus, we have covered all the possibilities for boys except for the pair of brother and sister having Economics and Sociology. Clearly since Amitabh and Bhagyashree are the only brother and sister mentioned in the information, they must be the ones having those subjects. Consequently Dharmendra must be having Zoology and Farhan would have Statistics. Commerce, Urdu and Computers would be shared between Chunky, Ekta and Govinda in some random order. Hence, they must be girls. The resultant table can be drawn as follows:
Brother of Bhagyashree Sister of Amitabh Girl Boy Girl Boy Girl Amitabh Bhagyashree Chunky Dharmendra Ekta Farhan Govinda Economics √ X X X X X X Commerce X X ???? X ???? X ???? Zoology X X X √ X X X Sociology X √ X X X X X Statistics X X X X X √ X Urdu X X ???? X ???? X ???? Computers X X ???? X ???? X ????
The answer is: Option (d) is the correct answer as we do not know who Dharmendra’s sister is.
Ans .
c
- Explanation :
Let us tabulate the given information to get a clear picture of the scenario. The first piece of information that fills the blanks is that no boy likes Commerce or Urdu. Then next information that is useful is that Dharmendra does not prefer Sociology and Statistics and is a boy hence he does not like Urdu and Commerce also. He is also brother of the person who opts for Computers. (Thus the person opting for computers must be a girl). So he must be having either Economics or Zoology. Now we are given that Amitabh and Bhagyashree are brother and sister and, hence Amitabh and Bhagyashree both will not have computers. Also Farhan is given as a boy student hence, by default from previous information, he does not like Urdu and Commerce, and also since he is a boy he cannot be Dharmendra’s sister and thus cannot have computers. Thus, we have covered all the possibilities for boys except for the pair of brother and sister having Economics and Sociology. Clearly since Amitabh and Bhagyashree are the only brother and sister mentioned in the information, they must be the ones having those subjects. Consequently Dharmendra must be having Zoology and Farhan would have Statistics. Commerce, Urdu and Computers would be shared between Chunky, Ekta and Govinda in some random order. Hence, they must be girls. The resultant table can be drawn as follows:
Brother of Bhagyashree Sister of Amitabh Girl Boy Girl Boy Girl Amitabh Bhagyashree Chunky Dharmendra Ekta Farhan Govinda Economics √ X X X X X X Commerce X X ???? X ???? X ???? Zoology X X X √ X X X Sociology X √ X X X X X Statistics X X X X X √ X Urdu X X ???? X ???? X ???? Computers X X ???? X ???? X ????
The answer is:Option (c) is the correct answer as there are 4 girls in the group.
Directions for Question 42 to 43:
Answer the questions by studying the information given below.
Five colleagues met at the party. While chatting that night they discovered that each of them has a
favourite TV show that airs one night during the week. By coincidence, each of them loves a different
show, each of which airs on a different night and channel. Given below are a few clues about the full
name of each colleague, the genre their favourite show is in, the night each show airs, and the channel
the show airs on (one of the channel is Channel 6).
(a) Manmohan didn’t watch a show on Friday night. Mr. Obama watched his favourite show on
Channel 21, the highest numbered channel. The favourite shows airing on Tuesday and
Thursday night were on channels one number apart.
(b) The man who watched the western show on Channel 7 didn’t watch TV on Wednesday night.
Mark watched a channel one digit lower than the man who watched the sports show.
(c) Mr. Singh watched the show on Channel 5, the lowest-numbered channel. The science fiction
show aired on Channel 12.
(d) Barack didn’t watch TV on Monday night. Mr. Twain didn’t watch the action show.
Manmohan didn’t watch the sports show.
(e) Gordon’s favourite show aired on a channel higher than the Tuesday night show but lower
than the show that Charles watched.
(f) The five colleagues watched their favourite shows during the week in the following order:
Mark, the man who watched Channel 7, the man who watched the mystery, Mr. Brown, and
Mr. Babbage.
Ans .
c
- Explanation :
From the given information a table can be formed which will give a clear picture of the scenario.
First Name Last Name Program Day Channel Barack Brown Sports Thursday 4 Gordon Babbage Science Fiction Friday 12 Manmohan Twain Western Tuesday 7 Mark Singh Action Monday 5 Charles Obama Mystery Wednesday 21
Option (c) is the correct answer.
Ans .
d
- Explanation :
From the given information a table can be formed which will give a clear picture of the scenario.
First Name Last Name Program Day Channel Barack Brown Sports Thursday 4 Gordon Babbage Science Fiction Friday 12 Manmohan Twain Western Tuesday 7 Mark Singh Action Monday 5 Charles Obama Mystery Wednesday 21
Option (d) is the correct answer.
Directions for Questions 44 to 45:
Read the following information and answer the questions that
follow.
Houses numbered 1A to 4D situated east to west in that order, are each occupied by College of
Commerce professors. They all teach different subjects, possess different makes and different models
(years) of bikes:
(i) Anurag Kesarwani does not own a Suzuki (owner of which is professor of Gujrati language).
(ii) Anshul has a Honda bike.
(iii) Mr. Khanduja lives in House No. 3.
(iv) Mr. Singh is the professor of Sanskrit language.
(v) 2001 model of bike owned by the Urdu language professor is not of BMW make.
(vi) Vivek is the professor of Bengali language.
(vii) Mr. Saxena is not the owner of 2004 model bike, owner of which lives next to in a house
westward of one owning 2002 model bike.
(viii)Siddhartha’s is House No. 4.
Ans .
c
- Explanation :
To solve the question, we have to decode the information step by step and hence interpret the information.
Anshul owns the Honda and Vivek teaches Bengali => Gujrati teacher owning Suzuki – who isn’t Anurag Kesarwani – is Siddhartha in House No. 4D (Clues (ii), (vi), (i), (viii)).
Prof. Singh who teaches Sanskrit is Anshul (Clue (iv)). Anurag Kesarwani, who teaches Urdu owns 2001 model bike which is not BMW (Clue (v)), neither is it Suzuki nor Honda – an unknown make. So, Vivek Khanduja owns BMW in House No. 3C and Siddhartha’s surname is Saxena (Clue (iii)).
Since Siddhartha’s vehicle is not a 2002 or 2004 model (Clue (vii)) and neither a 2001 model – it is model of an unknown year (which could be 2005 or an earlier year). Now 2002 model belongs to House No. 2 and 2004 model to House No. 4. Anshul Singh’s is 2002 model and Vivek Khanduja’s is 2003 model. Remaining House No. 1A is Anurag Kesarwani’s.
The summary is as under
Anurag – Kesarwani – Urdu –???? – 2001
Anshul – Singh – Sanskrit – Honda – 2002
Vivek – Khanduja – Bengali – BMW – 2003
Siddhartha – Saxena – Gujrati – Suzuki – ????
Option (c) is the correct answer.
Ans .
d
- Explanation :
To solve the question, we have to decode the information step by step and hence interpret the information.
Anshul owns the Honda and Vivek teaches Bengali => Gujrati teacher owning Suzuki – who isn’t Anurag Kesarwani – is Siddhartha in House No. 4D (Clues (ii), (vi), (i), (viii)).
Prof. Singh who teaches Sanskrit is Anshul (Clue (iv)). Anurag Kesarwani, who teaches Urdu owns 2001 model bike which is not BMW (Clue (v)), neither is it Suzuki nor Honda – an unknown make. So, Vivek Khanduja owns BMW in House No. 3C and Siddhartha’s surname is Saxena (Clue (iii)).
Since Siddhartha’s vehicle is not a 2002 or 2004 model (Clue (vii)) and neither a 2001 model – it is model of an unknown year (which could be 2005 or an earlier year). Now 2002 model belongs to House No. 2 and 2004 model to House No. 4. Anshul Singh’s is 2002 model and Vivek Khanduja’s is 2003 model. Remaining House No. 1A is Anurag Kesarwani’s.
The summary is as under
Anurag – Kesarwani – Urdu –???? – 2001
Anshul – Singh – Sanskrit – Honda – 2002
Vivek – Khanduja – Bengali – BMW – 2003
Siddhartha – Saxena – Gujrati – Suzuki – ????
Option (d) is the correct answer.
Directions for Questions 46 to 48:
Study the following information carefully and answer the
questions given below:
Five friends Michael, Mark, Lewis, Karan and Jenson are students of five different disciplines—
medical, engineering, architecture, arts, management and each plays a different musical instrument—
sitar, tabla, sarod, guitar and violin.
Lewis, a medical student, does not play sarod or sitar nor guitar.
Jenson is neither a student of Engineering nor Management.
Karan, who plays tabla, is an Arts student.
Neither Jenson nor Michael plays sarod.
Ans .
b
- Explanation :
To understand the arrangement we need to tabulate all the clues and facts given in the question.
DISCIPLINE MUSICAL INSTRUMENTS NAME MEDICAL ENGG. ARCH. ART MGMT SITAR TABLA SAROD GUITAR VIOLIN MARK X ???? X X ???? X X √ X X MICHAEL X ???? X X ???? ???? X X ???? X LEWIS √ X X X X X X X X √ KARAN X X X √ X X √ X X X JENSON X X √ X X ???? X X ???? X
Hence Option (b) is the correct answer.
Ans .
d
- Explanation :
To understand the arrangement we need to tabulate all the clues and facts given in the question.
DISCIPLINE MUSICAL INSTRUMENTS NAME MEDICAL ENGG. ARCH. ART MGMT SITAR TABLA SAROD GUITAR VIOLIN MARK X ???? X X ???? X X √ X X MICHAEL X ???? X X ???? ???? X X ???? X LEWIS √ X X X X X X X X √ KARAN X X X √ X X √ X X X JENSON X X √ X X ???? X X ???? X
There is a choice of Engineering, Architecture and Management. Hence Option (d) is the correct answer.
Ans .
d
- Explanation :
To understand the arrangement we need to tabulate all the clues and facts given in the question.
DISCIPLINE MUSICAL INSTRUMENTS NAME MEDICAL ENGG. ARCH. ART MGMT SITAR TABLA SAROD GUITAR VIOLIN MARK X ???? X X ???? X X √ X X MICHAEL X ???? X X ???? ???? X X ???? X LEWIS √ X X X X X X X X √ KARAN X X X √ X X √ X X X JENSON X X √ X X ???? X X ???? X
No clear clue provided hence Option (d) is the correct answer.
Directions for Questions 49 to 51:
Read the information and answer the questions that follow.
Five friends—Ramesh, Suresh, Tanveer, Umesh, and Vikram—each present one paper to their class
on mathematics, history, biology, chemistry, or dermatology—one day a week, Monday through
Friday.
(i) Vikram does not do chemistry and does not give his presentation on Tuesday.
(ii) Suresh makes the dermatology presentation, and does not do it on Monday or Friday.
(iii) The mathematics presentation is made on Thursday.
(iv) Tanveer presents his presentation, which is not on Chemistry, on Wednesday.
(v) The biology presentation is on Friday, and not by Umesh.
(vi) Ramesh makes his presentation on Monday.
Ans .
b
- Explanation :
The following solution table would emerge out of these clues.
Day Monday Tuesday Wednesday Thursday Friday Person Ramesh Suresh Tanveer Umesh Vikram Presentation topic Chemistry Dermatology History Mathematics Biology
Monday. Option (b)
Ans .
d
- Explanation :
The following solution table would emerge out of these clues.
Day Monday Tuesday Wednesday Thursday Friday Person Ramesh Suresh Tanveer Umesh Vikram Presentation topic Chemistry Dermatology History Mathematics Biology
Biology. Option (d)
Ans .
d
- Explanation :
The following solution table would emerge out of these clues.
Day Monday Tuesday Wednesday Thursday Friday Person Ramesh Suresh Tanveer Umesh Vikram Presentation topic Chemistry Dermatology History Mathematics Biology
Thursday. Option (d)