# PIE-CHARTS

The following pie-chart shows the sources of funds to be collected by the National

Highways Authority of India (NHAI) for its Phase II projects. Study the pie-chart and answer

the questions that follow.

Total funds to be arranged for Projects (Phase II) =Rs.57,600 crores.

Ans .

External Assistance

1. Explanation :

20% of the total funds to be arranged = Rs.(20% of 57600) crores

= Rs.11520 crores Rs.11486 crores.

Ans .

($$187.2^{\circ}$$

1. Explanation :

Central angle corresponding to Market Borrowing = $$[\frac{29952}{57600}*360]^{\circ}$$= ($$187.2^{\circ}$$

Ans .

1:6

1. Explanation :

Required ratio = $$\frac{4910}{29952}$$= $$\frac{1}{6.1}$$ =$$\frac{1}{6}$$

Ans .

6%

1. Explanation :

Shortage of funds arranged through External Assistance

=Rs.(11486-9695) crores =Rs. 1791 crores.

therefore, Increase required in Market Borrowings =Rs. 1791 crores.

Percentage increase required = $$\frac{1791}{29952}$$* 100 % = 5.98 % = 6%

Ans .

Rs. 5401 crores

1. Explanation :

Amount permitted = (Funds required from Toll for projects of Phase II ) +(10 % of these funds)

=Rs. 4910 crores + Rs. (10% of 4910) crores

=Rs. (4910 + 491) crores = Rs. 5401 crores.

The pie-chart provided below gives the distribution of land (in a village) under

various food crops. Study the pie-chart carefully and answer the questions that follow.

DISTRIBUTION OF AREAS (IN ACRES) UNDER VARIOUS FOOD CROPS

Ans .

Rice, Wheat and Barley

1. Explanation :

The total of the central angles corresponding to the three crops which cover 50% of the

total area ,should be 180?.Now, the total of the central angles for the given combinations are:

(i) Wheat,Barley and jowar =$$72^{\circ}$$+ $$36^{\circ}$$+ $$18^{\circ}$$ =$$126^{\circ}$$

(ii) Rice,Wheat and Jowar = $$72^{\circ}$$+$$72^{\circ}$$+$$18^{\circ}$$=$$162^{\circ}$$

(iii) Rice,Wheat and Barley = $$72^{\circ}$$+$$72^{\circ}$$+$$36^{\circ}$$=$$180^{\circ}$$

(iv)Bajra,Maize and Rice = $$18^{\circ}$$+ $$45^{\circ}$$+$$72^{\circ}$$ = $$135^{\circ}$$

Clearly:(iii) is the required combination.

Ans .

6

1. Explanation :

The area under any of the food crops is proportional to the angle corresponding to that crop.

Let the area under the rice production be x million acres.

Then, 18:72 = 1.5:x =>x=(72*15/18)=6

Thus, the area under rice production be = 6 million acres.

Ans .

3:1

1. Explanation :

Let the total production of barley be T tones and let Z acres of land be put under barley production.

Then, the total production of wheat =(6T) tones.

Also,area under wheat production = (2Z) acres.

$$\frac{Area Under Wheat Production}{Area Under Barley Production}$$=$$\frac{72^{\circ}}{36^{\circ}}$$=2

And therefore,Area under wheat = 2*Area under Barley = (2Z)acres

Now, yield per acre for wheat = (6T/2Z) tones/acre = (3T/Z) tones/acre

And yield per acre for barley = (T/Z) tones/acre.

Required ratio = $$\frac{3T/Z}{T/Z}$$= 3:1.

Ans .

33%

1. Explanation :

Let Z acres of land be put under barley production.

$$\frac{Area Under Wheat Production}{Area Under Barley Production}$$=$$\frac{75^{\circ}}{36^{\circ}}$$=2

Area under rice production = 2 * area under barley production = (2Z) acres.

Now,if p tones be the yield per acre of barley then ,yield per acre of rice=(p+50% of p) tones =(3/2 p) tones.

Total production of rice = (yield per acre) * (area under production)= (3/2 p)*2Z=(3pZ) tones.

And,Total production of barley = (pz) tones.

Percentage production of barley to that rice = (pZ/3pZ *100)%= 33 1/3%

Ans .

$$76.8^{\circ}$$

1. Explanation :

Initially,let t be the total area under considerations.

The area under wheat production initially was =(72/360 * t)acres = (t/5)acres.

Now,if the total area under consideration be increased by 5%,

then the new value of the total area= (105/100 t) acres.

Also,if the area under wheat production be increased by 12%,

then the new value of area under wheat =|$$\frac{t}{5}$$ +(12% of $$\frac{t}{5}$$)| acres = (112t/500)acres.

Central angle corresponding to wheat in the pie-chart

= $$[\frac{Area Under Wheat (new)}{Total area (new)}*360]^{\circ}$$ = $$[\frac{(112t/500)}{(105t/100)}$$*360]^{\circ}\) =$$76.8^{\circ}$$

The following pie-charts show the distribution of students of graduate and post graduate levels in seven different institute-M,N,P,Q,R,S and T in a town.

DISTRIBUTION OF STUDENTS AT GRADUATE AND POST-GRADUATE LEVELS IN SEVEN INSTITUTES-M,N,P,Q,R,S AND T.

Ans .

(b) 8463

1. Explanation :

Students of institute M at graduate level = 17% of 27300 = 4641.

Students of institute S at graduate level = 14% of 27300 = 3822

Total number students at graduate level in institutes M and S = 4641+3822=8463.

Ans .

(c) 6669

1. Explanation :

Required number = (15% of 24700) + (12% of 24700) = 3705 + 2964 = 6669

Ans .

(d) 8372

1. Explanation :

Required number = (18% of 27300) + (14% of 24700) = 4914 + 3458 = 8372.

Ans .

(d) 19:14

1. Explanation :

Required ratio =$$\frac{21% of 24700}{14% of 27300}$$ = $$\frac{21 * 24700}{14 * 27300}$$ = $$\frac{19}{14}$$

Ans .

(d)19:13

1. Explanation :

Required ratio =$$\frac{21% of 24700}{14% of 27300}$$ = $$\frac{(21 * 24700)}{(13* 27300)}$$ = $$\frac{19}{13}$$

Study the following pie-chart and the table and the answer the questions based on them.

PROPORTION OF POPULATION OF SEVEN VILLAGES IN 1997

Ans .

22000.

1. Explanation :

Let the population of village X be x

Then,38% of x=12160 => x = $$\frac{12160 * 100}{38}$$ =3200

Now ,if s be the population village S,then

16:11 = 32000 : s => s= $$\frac{11 * 32000}{16}$$= 22000.

Ans .

23:11

1. Explanation :

Let N be the total population of all the seven villages.

Then ,population of village T below poverty line = 46% of (21% of N) and population of village Z

below poverty line = 42% of (11% of N)

Required ratio =$$\frac{46percent of 21percent of N}{42percent of 11percent of N}$$ = $$\frac{46*21}{42*11}$$ = $$\frac{23}{11}$$

Ans .

15600

1. Explanation :

Population of village R = 32000(given)

Let the population of village Y be y.

Then, 16:15 = 32000 : y => y = $$\frac{15 * 32000}{16}$$= 30000.

Ans .

12760

1. Explanation :

Population of village Y in 1997 = 30000(given) .

Let the population village V in 1997 be v.

Then, 15:10 = 30000:v => v = $$\frac{10 * 30000}{15}$$= 20000.

Now population of village V in 1998 = 20000 + (10% 0f 20000) = 20000.

Population of village V below poverty line in 1998 = 58% of 22000 = 12760.

Ans .

2:1

1. Explanation :

Let the total population of all the seven villages in 1997 be N.

Then,population of village R in 1997 = 16% of N = 16/ 100 N

And population of village Z in 1997 = 11% of N =11/100 N

Population of village R in 1999 = {16/100N+(10% of 16/100 N)}=1760/10000 N

and population of village Z in 1999 = {11/100 N-(5% of 11/100 N)} = 1045/10000 N.

Now,population of village R below poverty line for 1999 = 51% of(1760/10000 N)

And population of village Z below poverty line 1999 = 42% of (1045/10000 N)

Required ratio =$$\frac{51 percent of 1760/10000 N}{42 percent of 1045/10000 N}$$ = $$\frac{51 * 1760 }{42 * 1045}$$ = $$\frac{2}{1}$$