The following table gives the sales of batteries manufactured by a company

lit the years. Study the table and answer the questions that follow:

YEAR | 4AH | 7AH | 32AH | 35AH | 55AH | T0TAL |
---|---|---|---|---|---|---|

1992 | 75 | 144 | 114 | 102 | 108 | 543 |

1993 | 90 | 126 | 102 | 84 | 426 | 528 |

1994 | 96 | 114 | 75 | 105 | 135 | 525 |

1995 | 105 | 90 | 150 | 90 | 75 | 510 |

1996 | 90 | 75 | 135 | 75 | 90 | 465 |

1997 | 105 | 60 | 165 | 45 | 120 | 495 |

1998 | 115 | 85 | 160 | 100 | 145 | 605 |

**Ans . **

32AH

**Explanation :**The total sales (in thousands) of all the seven years for various batteries are:

For 4AH = 75 + 90 + 96 + 105 + 90 + 105 + 115 = 676

For 7AH = 144 + 126 + 114 + 90 + 75 + 60 + 85 = 694

For 32AH = 114 + 102 + 75 + 150 + 135 + 165 + 160 = 901

For 35 AH= 102 + 84 + 105 + 90 + 75 + 45 + 100 = 601

For 55 AH= 108 + 126 + 135 + 75 + 90 + 120 + 145 = 799.

Clearly, sales are maximum in case of 32AH batteries.

**Ans . **

39000

**Explanation :**Required difference = [(84 - 45) x 1000] = 39000

**Ans . **

1997

**Explanation :**The percentages of sales of 4AH batteries to the total sales in different years are:

For 1992 =(75*100/543)%=13.81%

For 1993=(90*100)/528%=17.05%

For 1994=(96*100/465)%=19.35%

For 1995=(105*100/495)%=20.59%

For 1996=(96*100/465)%=19.35%

For 1997=(105*100/495)%=21.21%

For 1998=(115*100/605)%=19.01%

Clearly, the percentage is maximum in 1997.

**Ans . **

35AH

**Explanation :**From the table it is clear that the sales of 7AH batteries have

been decreasing continuously from 1992 to 1997.

**Ans . **

34%.

**Explanation :**Required Percentage =(145-108)/108)*100 %=34.26%=34%.

Study the following table carefully and answer these questions:

NUMBER OF CANDIDATES APPEARED AND QUALIFIED IN A COMPETITIVE

EXAMINATION FROM DIFFERENT STATES OVER THE YEAR

1997 | 1998 | 1999 | 2000 | 2001 | ||||||
---|---|---|---|---|---|---|---|---|---|---|

App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | |

M | 5200 | 720 | 8500 | 980 | 7400 | 850 | 6800 | 775 | 9500 | 1125 |

N | 7500 | 840 | 9200 | 1050 | 8450 | 920 | 9200 | 980 | 8800 | 1020 |

P | 6400 | 780 | 8800 | 1020 | 7800 | 890 | 8750 | 1010 | 9750 | 1250 |

Q | 8100 | 950 | 9500 | 1240 | 8700 | 980 | 9700 | 1200 | 8950 | 995 |

R | 7800 | 870 | 7600 | 940 | 9800 | 1350 | 7600 | 945 | 7990 | 885 |

**Ans . **

12.35%

**Explanation :**Required Percentage=(1020+1240) *100%=(2260*100)/18300%

(8800+9500)=12.35%

**Ans . **

11.84%.

**Explanation :**Required Percentage= (850+920+890+980+1350) *100% (7400+8450+7800+8700+9800)

=(4990*100)/42150%

=11.84%.

**Ans . **

=11.15%

**Explanation :**Required Percentage=(84+1050+920+980+1020)/(7500+9200+8450+9200+8800)*100%=(4810*100)/43150*) %

=11.15%

**Ans . **

8990

**Explanation :**Required average =(8100+9500+8700+9700+8950)/5=44950/5=8990

**Ans . **

2001

**Explanation :**The percentages of candidates qualified to candidates appeared from

State P during different years are:

For 1997= 780 * 100% =12.19% 6400

for 1998 = 1020*100 %=11.59% 8800

For 1999 = 890*100 %=11.41%; 7800

For 2000 = 1010* 100 % = 11.54%. 8 750

For 2001=1250*100 %= 12.82% 9750

Maximum percentage is for the year 2001..

**Ans . **

80%

**Explanation :**Required Percentage =( 720 + 840 + 780 + 950 + 870) . x 100

980+1050+1020+1240+940=80%

The following table gives the percentage of marks obtained by seven students in six , different subjects in an examination. Study the table and

answer the questions based on it. The numbers in the brackets give the maximum marks in each subject.

Student | Maths | Chemistry | Physics | Geography | History | Computer Science |
---|---|---|---|---|---|---|

Max Marks | (160) | (130) | (120) | (100) | (60) | (40) |

Ayush | 90 | 50 | 90 | 60 | 70 | 80 |

Aman | 100 | 80 | 80 | 40 | 80 | 70 |

sajal | 90 | 60 | 70 | 70 | 90 | 70 |

Rohit | 80 | 65 | 80 | 80 | 60 | 60 |

Muskan | 80 | 65 | 85 | 95 | 50 | 90 |

Tanvi | 70 | 75 | 65 | 85 | 40 | 60 |

**Ans . **

449

**Explanation :**Aggregate marks obtained by Sajal

= [(90% of 150) + (60% of 130) + (70% of 120) + (70% of 100) +(90% of 60) + (70% of 40)] = 135 + 78 + 84 + 70 + 54 + 28 = 449.

**Ans . **

60%.

**Explanation :**Aggregate marks obtained by Tarun .

= [(65% of 150) + (35% of 130) + (50% of 120) + (77% of 100) + (80% of60) + (80% of 40)] = 97.5 + 45.5 + 60 + 77 + 48 + 32 = 360.

Total maximum marks (of all the six subjects)

= (150 + 130 + 120 + 100 + 60 + 40) = 600.

Overall percentage of Tarun = 360 x 100 % = 60%.

**Ans . **

89.14

**Explanation :**Average marks obtained in Physics by all the seven students

= 1/7 [(90% of 120) + (80% of 120) + (70% of 120) + (80% of 120)+ (85% of 120) + (65% of 120) + (50% of 120)]

= 1/7 [(90 + 80 + 70 +80 + 85 + 65 + 50)% of 120]

=1/7 [520% of 120] = 89.14.

**Ans . **

2

**Explanation :**From the table it is clear that Sajal and Rohit have 60% or more

marks in each of the six subjects.

**Ans . **

Maths

**Explanation :**We shall find the overall percentage (for all the seven students) with respect to each subject.The overall percentage for any subject is equal to the average of percentages obtained by all the seven students since the maximum marks for any subject is the same for all the students.Therefore, overall percentage for:

(i) Maths = [1/7(90+100+90+80+80+70+65)]%= [1/7(575)]% = 82.14%.

(ii) Chemistry = [1/7(50 + 80 + 60 + 65 + 65 + 75 + 35)]%= [1/7(430)]% = 61.43%. .

(iii) Physics = [1/7(90 + 80 + 70 + 80 + 85 + 65 + 50)]%=[1/7 (520)]% = 74.29%.

(iv) Geography = [1/7(60 + 40 + 70 + 80 + 95 + 85 + 77)]%= [1/7 (507)} = 72.43%.

(v) History = [1/7 (70 + 80 + 90+ 60 + 50 + 40 + 80)]%=1/7 [(470)]% = 67.14%.

(vi) Computer Science = [1/7 (80 + 70 + 70 + 60 + 90 + 60 + 80)]%= [1/7 (510)]% = 72.86%.

Clearly; this. percentage is highest for Maths.

Study the following table carefully and answer tbe questions given below:(Bank P.O. 2001) CLASSIFICATION OF 100 STUDENTS BASED ON THE MARKS OBTAINED BY THEM IN PHYSICS AND CHEMISTRY IN AN EXAMINATION

(Marks out Of 50) Subject | 40 and above | 30 and above | 20 and above | 10 and above | 0 and above |
---|---|---|---|---|---|

physics | 9 | 32 | 80 | 92 | 100 |

chemistry | 4 | 21 | 66 | 81 | 100 |

(aggregate Average) | 7 | 27 | 73 | 87 | 100 |

**Ans . **

27

**Explanation :**We have 40% of 50 =(40/100 x 50)= 20.

Required number = Number of students scoring less than 20 marks in aggregate

= 100 - number of students scoring 20 and above marks in aggregate = 100 - 73 = 27.

**Ans . **

32

**Explanation :**We have 60% of 50 =(60 /100x 50) = 30.

Required number = Number of students scoring 30 and above mark in Physics = 32

**Ans . **

6

**Explanation :**Required difference = (Number of students scoring 30 and

above in mark in Chemistry) (Number of students scoring 30 and above marks in aggregate) = 27 - 21 = 6.

**Ans . **

29%

**Explanation :**Number of students getting at least 60% marks in Chemistry

= Number of students getting 30 and above marks in Chemistry = 21.

Number of students getting at least 40% marks in aggregate

= Number of students getting 20 and above marks in aggregate = 73.

Required Percentage = (21/73x 100)% = 28.77% ˜29%.

**Ans . **

20-30

**Explanation :**Since 66 students get 20 and above marks in Chemistry and out of

these 21 students get 30 and above marks, therefore to select top 35 students in Chemistry, the qualifying marks

should lie in the range 20-30.