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Q.1

Find the present worth of Rs. 930 due 3 years hence at

8% per annum. Also find the discount.

Rs. 180

Rs. 102

Rs. 192

Rs. 132

Ans .

Rs. 180

Explanation :
P.W=100 x Amount /[100 + (R x T)]
=Rs.100 x 930/100+ (8x3)
= (100x930)/124= Rs. 750,
T.D. = (Amount) - (P.W.) = Rs. (930 - 750) = Rs. 180.

Q.2

The true discount on a bill due 9 months hence at 12%

per annum is Rs. Find the amount of the bill and its present worth..

Rs. 5000

Rs. 4500

Rs. 6000

Rs.5500

Ans .

Rs. 6000

Explanation :
Let amount be Rs. x.
Then,x*R*T/100 + (R x T)
=T.D.=>x*12*(3/ 4)/[100+[12*3/4]]=540
x= 540x109 = Rs.6540
Amount - Rs. 6540. P.W. = Rs. (6540 - 540) - Rs. 6000..

Q.3

The true discount on a certain sum of money due 3 years

hence is Rb. 250 and the simple interest on the same sum for the same time and

at the same rate is Rs. 375. Find the sumand the rate percent.

16 2/3%.

16 1/5%.

11 5/3%.

13 1/3%.

Ans .

16 2/3%.

Explanation :
T.D. = Rs. 250 and S.I. = Rs. 375.
Sum due =S.I. xT.D./ S.I. -T.D.=375x250/375- 250=Rs.750.
Rate=[100*375/750*3]%=16 2/3%.

Q.4

The difference between the simple interest and true discount on a certain sum

of money for 6 months at 12% per annum is Rs. 25. Find the sum.

Rs.5500

Rs. 6200

Rs.5800

Rs. 6800

Ans .

Rs. 6800

Explanation :
Let the sum be Rs. x. Then,
T.D. = (x*25/2*1/2)/(100+(25/2*1/2))=x*25/4*4/425=x/17
S.I=x*25/2*1/2*1/100=x/16
x/16-x/17=25 =>17x-16x=25*16*17 =>x=6800
Hence, sum due = Rs. 6800..

Q.5

A bill falls due in 1 year. The creditor agrees to accept immediate payment of the half and to defer the payment of the

other half for 2 years. By this arrangement ins Rs. 40. What is the amount of the bill, if the money be worth 12% ?.

Rs. 3200

Rs. 3000

Rs. 3600

Rs. 3500

Ans .

Rs. 3600

Explanation :
Let the sum be Rs. x. Then,
[x/2+(x/2*100)/100+(25/2*2)]-[(x*100)/(100+25/2*1]=40
=>x/2+2x/5-8x/9=40=>x=3600
Amount of the bill - Rs. 3600

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