Let Rajeev's present age be x years. Then, Rajeev's age after 15 years = (x + 15) years. Rajeev's age 5 years back = (x - 5) years.
x + 15 = 5 (x - 5) x + 15 = 5x - 25 4x = 40 x = 10.Hence, Rajeev's present age = 10 years.
Let the age of the younger person be x years. Then, age of the elder person = (x + 16) years.
3(x - 6) = (x + 16 - 6) 3x-18 = x + 10 2x = 28 x = 14.Hence, their present ages are 14 years and 30 years.
Let Ankit's age be x years. Then, Nikita's age = 240/x years.
2*(240 /x ) – x = 4 480 – x * x = 4x x * x + 4x – 480 = 0 ( x+24)(x-20) = 0 x = 20.Hence, Nikita's age = 240 / 20 years = 12 years.
Sol. Let the son's present age be x years. Then, father's present age = (3x + 3) years
(3x + 3 + 3) = 2 (x + 3) + 10
3x + 6 = 2x + 16
x = 10.
Hence, father's present age = (3x + 3) = ((3 * 10) + 3) years = 33 years.
Let son's age 8 years ago be x years. Then, Rohit's age 8 years ago = 4x years. Son's age after 8 years = (x + 8) + 8 = (x + 16) years. Rohit's age after 8 years = (4x + 8) + 8 = (4x+ 16) years.
2 (x + 16) = 4x + 16 2x = 16 x = 8Hence, son's 'present age = (x + 8) = 16 years. Rohit's present age = (4x + 8) = 40 years.
. Let Gaurav's and Sachin's ages one year ago be 6x and 7x years respectively. Then, Gaurav's age 4 years hence = (6x + 1) + 4 = (6x + 5) years.
Sachin's age 4 years hence = (7x + 1) + 4 = (7x + 5) years.
\(\frac{6x+5}{7x+5}=\frac{7}{8}\) --> 8 (6x+5) = 7 (7x + 5) --> 48x + 40 = 49x + 35 --> x = 5.Hence, Sachin's present age = (7x + 1) = 36 years.
. Let the ages of Abhay and his father 10 years ago be x and 5x years respectively. Then, Abhay's age after 6 years = (x + 10) + 6 = (x + 16) years.
Father's age after 6 years = (5x + 10) + 6 = (5x + 16) years.
( x + 16) = 3/7 *(5x + 16) 7 (x + 16) = 3 (5x + 16) 7x + 112 = 15x + 48 8x = 64 x = 8.Hence, Abhay's father's present age = (5x + 10) = 50 years.