There are 5 different hardware interrupts
these are RST 5.5, RST 6.5, RST 7.5, INTR, TRAP
Ans .
(A) DAD D
Explanation :
DAD D instruction Add 16 bits register pair with H2 register.
Ans .
(C) Interrupt request register
Explanation :
Interrupt request register (IRR) holds all requests of interrupt.
Ans .
(B) Base indexed plus displacement
Explanation :
Here option A is also correct if exact condition is not given otherwise option B is correct.
Ans .
(A) Write through
Explanation :
Write through method change the content of memory from cache to main memory or main memory to hard disk etc. in parallel
Ans .
(C) Object-oriented databases are more adapt at handling structures (analytical) data than relational databases.
Explanation :
Ans .
(B) Fragments
Explanation :
Ans .
(D) I, III and III are the same query.
Explanation :
πA,B(R⋈ S), R⋈ πB(S), R∩(πA(R) Χ πB(S)) returns rows from R where R.B=S.B Whereas πA,R.B(R Χ S) where R.B refers to the column B in table R returns R itself.
Ans .
(B) Neither D1 and D2
Explanation :
D1 is wrong because no functional dependencies is specified.
Ans .
(A) M=4, N=2
Explanation :
Ans .
(C) Only the joining attributes are sent from one site to another and then only the required rows are returned.
Explanation :
Ans .
(B) xi+1 = xi + 1 yi+1 = yi - 1 pi+1 = pi + 4(xi - yi) + 10
Explanation :
Ans .
(A) (3,5)
Explanation :
Ans .
(D) AB and CD
Explanation :
Ans .
(C) Topological distortion
Explanation :
Ans .
(C) x’ = x y’ = Shy(x - xref) + y
Explanation :
Ans .
(D) I, II and III only
Explanation :
Ans .
(D) (a), (b) and (c) are true.
Explanation :
Ans .
C or A
Explanation :
Stack dynamic in Fortran 77, Explicit heap dynamic for all objects of JAVA Implicit heap dynamicsfor all variables in APL but Pascal does not contain static variable So option (A) is most appropriate. else option C is correct
Ans .
(D) Hardware maintenance cost
Explanation :
Ans .
(C) The family of regular languages are closed under both symmetric difference and nor.
Explanation :
Ans .
(D) (λ + a + aa + aaa)b* + a*bbbbb* + (a + b)*ba(a + b)*
Explanation :
Ans .
(B) L1 is not regular and L2* is regular
Explanation :
Both languagesare not regular but L2* becomes gcd of two numbers can't be determined by DFA or regular expression subset of 0* is ap where p is prime number which is also not regular language but (ap)* is regular So any language over single E then Kleen star of that language becomes regular language.
Ans .
(C) 32 Kbps
Explanation :
If one slot holds only a single frame then
4000 frames/sec means 4000 slots/sec and each having 8 bits
thus bit rate = 4000*8=32000 bits/sec= 32 Kbps.
Ans .
(D) (a), (b) and (d) are true; (c) is false.
Explanation :
Ans .
(B) 0.184
Explanation :
Frame size=200 bit
data rate= 200 Kbps
Tx delay=2000/(2000*103)= 10-3 sec = 1ms
Frame generation rate=500/sec
no. of slots in a sec =1000
i.e. 500 frames/ 1000slots
or 1 frame/2 slots
In pure aloha this load results in max throughput of 0.184
Ans .
(B) (iii) (iv) (ii) (i)
Explanation :
Ans .
Marks Given to all
Explanation :
Ans .
(A) TAXERTZENZ
Explanation :
Ans .
(C) 132
Explanation :
Ans .
(D) θ(n2)
Explanation :
Ans .
(C) [26, 15, 17, 14, 11, 9, 13]
Explanation :
Ans .
(C) (iii) (ii) (iv) (i)
Explanation :
The complexity of Huffman, optimal polygon, activity selection & cluster sort are θ(nlog n), θ(n2), θ(n) and θ(n2) in worst case (However same options contain big oh for other cases)
Ans .
(C) 926, 203, 912, 241, 913, 246, 364
Explanation :
Ans .
(B) n-3, n-2
Explanation :
For 5 vertex polynomial
3 chords and 4 triangles.
So (n-2 , n-1)
Ans .
(B) class type itself
Explanation :
Ans .
(B) 3
Explanation :
Ans .
(C) Aggregation is a weak type of association between two classes with partial ownership.
Explanation :
Ans .
B,C
Explanation :
Ans .
(D) HTML is a programming language.
Explanation :
HTML is a markup language.
Ans .
(B) a copy of the reference is created.
Explanation :
Ans .
(C) 98.3%
Explanation :
Server is not available for 12 hours after each 30 days
So 30*24+12= total hours
30*24= available hours
availablity=(30*24)/ (30*24+12)
=60/61
=.9836
=98.3%
LOC/FP=50= LOC/500
LOC=500*50=25,000
LO person-month/FP
=2.5*25
=62.5 person months
Ans .
(C) Zombie Processes
Explanation :
Ans .
(C) Shared memory segments
Explanation :
Ans .
(C) Each i-node is 256-bytes long.
Explanation :
File and directories are stored in inode block instead of data block.
Ans .
(D) KILL is a blockable signal.
Explanation :
KILL is a blockable signal because KILL removes complete process.
Ans .
(D) 30
Explanation :
Ans .
(B) 80 msec
Explanation :
A signal 3K RPC generaly takes 1.5 * 32 + 1 msec
i.e
49 ms 32 1K RPC takes 1.5 * 32 + 1 * 32 = 80 ms
Ans .
(A) 2
Explanation :
Hee 0*10* needs 3 states but option is not available so we can assume (wrongly) that dead state is not available, so most appropriate option is (A).
Ans .
(C) Both L’ and Lk is for any k≥1 are context free.
Explanation :
L' is CFG and Lk K>=1 becomes LLk which is also CFG.
Ans .
(C) aba*b
Explanation :
Ans .
(D) max H(x|y) p(x)
Explanation :
Chennel capacity of discrete memoryless channel is defined by
C= max I(x;y) p(x)
= max [H(y)-H(y/x)] p(x)
=max [H(x)-H(x/y)] p(x)
So option (D) is not channel capacity.